Answer:
Explanation:
How many mols do you have?
1 mol = 6.02 * 10^23 atoms
x mol = 6.25 * 10 ^32 atoms
1/x = 6.02*10^23 / 6.25 * 10^32 Cross multiply
6.02 * 10^23 * x = 1 * 6.25 * 10^32 Divide by 6.02 * 10^23
x = 6.25 * 10*32/ 6.02 ^10^23
x = 1.038 * 10^9 mols which is quite large.
Find the number of grams. (Use the value for copper on your periodic table. I will just use an approximate number.)\
1 mol of copper = 63 grams.
1.038 * 10^9 mols of copper = x
1/1.038 * 10^9 = 63/x Cross multiply
x = 1.038 * 10^9 * 63
x = 6.54 * 10^10 grams of copper.
Answer:
See explanation
Explanation:
The electron configuration of an atom in an element determines the property of the atom. The core electrons are found inside the atom while the valence electrons are found on the outermost shell of the atom.
For cobalt, the outermost shell electron configuration is; [Ar] 3d7 4s2. The 3d7 and 4s2 are found in the valence shell of cobalt.
For arsenic, the electronic configuration is [Ar] 3d¹⁰ 4s² 4p³. The valence electrons are 4s2, 4p3. The 3d electrons are found inside the arsenic atom.
Bb, or mostly dominant with a little recessive
<h2>Question↷</h2>
Which of these solutions is the most basic?
[OH-] = 4.3 x 10-9 M
[OH-] = 2.8 x 10-11 M
[OH-] = 6.7 x 10-10 M
[OH-] = 1.0 x 10-5 M
<h2>Answer↷</h2>
- <u>[OH-] = 1.0 x 10-5 M</u> ✓
<h2>Solution↷</h2>
[OH-] = 4.3 x 10-9 M
- [OH-] = 4.3 x 10^-9 M
- pOH = - log [OH^1-]
- pOH = - log [4.3 x 10^-9]
- pOH = 8.36
- pH = 14- 8.36
- pH = 5.64
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[OH-] = 2.8 x 10-11 M
- [OH-] = 2.8 x 10^-11 M
- pOH = - log [OH^1-]
- pOH = - log [2.8 x 10^-11 ]
- pOH = 10.55
- pH = 14-10.55
- pH = 3.45
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[OH-] = 6.7 x 10-10 M
- [OH-] = 6.7 x 10^-10 M
- pOH = - log [OH^1-]
- pOH = - log [6.7 x 10^-10]
- pOH = 9.17
- pH = 14-9.17
- pH = 4.83
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[OH-] = 1.0 x 10-5 M
- [OH-] = 1.0 x 10-5 M
- pOH = - log [OH^1-]
- pOH = - log [1.0 x 10^-5 ]
- pOH = 5
- pH = 14-5
- pH = 9
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we know that , the solution with <u>pH > 7</u> is termed as basic and more the pH ,more the basicity, hence ,the solution with the highest pH would be the strongest base out of these all which is
<u>[OH-] = 1.0 x 10-5 M</u> with pH = 9
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