<h2>
<u>Q</u><u>U</u><u>E</u><u>S</u><u>T</u><u>I</u><u>O</u><u>N</u><u>:</u></h2>
A demographer predicts that the population, P, of a town t years from now can be modeled by the function <u>P(t) = 6t^4 - 5t^3 + 200t + 12000</u>. What will the population of the town be two (2) years from now?
<h2>
<u>S</u><u>O</u><u>L</u><u>U</u><u>T</u><u>I</u><u>O</u><u>N</u><u>:</u></h2>
To calculate the population of the town be two (2) years from now, replace t into 2:
<h2>
<u>A</u><u>N</u><u>S</u><u>W</u><u>E</u><u>R</u><u>:</u></h2>
- The population of the town be two (2) years from now is <u>12, 456</u>.
If you would like to learn more about functions, kindly please take your time to visit this following links:
Usually when you see f(x) or as yours is f(6) f with parenthesis is just a fancy way of saying y= so basically you plug six in for the x values of your question
1st multiply -6y by 4y=-24y^2
2nd, multiply -6y by 3=-18y
3rd, multiply -7 by 4y=-28y
4th, multiply -7 by 3=-21
5th, write all the terms in standard form: -24y^2-18y-28y-21
Combine like terms:-18y-28y=-46y
Put in standard form: -24y^2-46y-21
Final Answer: -24y^2-46y-21
Answer:
700 lei
Step-by-step explanation:
You have a geometric sequence for which you know the common ratio and the last term.
There are only three terms, so you can solve the problem in either of two ways.
1. The brute force method
(easiest for only a few terms)
Each term is half the one before it, so each term is double the one after it.
3rd term = 100 lei
2nd term = 200
1st term = 400
Total = 700 lei
Oana spent 700 lei
2. Using formulas (best for longer sequences)
The general formula for your sequence is
aₙ = a₁rⁿ⁻¹
For your sequence,
a₃ = 100; r = 0.5
(a) Calculate a₁
Set the last term equal to the general formula.
a₃ = a₁(0.5)ⁿ⁻¹
100 = a₁(0.5)² = 0.25a₁
a₁ = 100/0.25 = 400
(b) Calculate the sum
The general formula for the sum of a geometric sequence is
Oana spent 700 lei.