Answer:
about $0.20 per kilowatt-hour. i hope this helps
Step-by-step explanation:
Answer:
15 inches
Step-by-step explanation:
We assume that the edge of the small square is x (inches).
As the edge of the larger square is 2 inches greater than that of the smaller one, so that the edge of the larger square = edge of the small square + 2 = x + 2 (inches)
The equation to calculate the are of a square is: <em>Area = Edge^2 </em>
So that:
+) The area of the larger square is: <em>Area large square = </em>
<em> (square inches)</em>
+) The area of the smaller square is: <em>Area small square = </em>
<em>(square inches)</em>
<em />
As difference in area of both squares are 64 square inches, so that we have:
<em>Area large square - Area small square = 64 (square inches)</em>
<em>=> </em>
<em />
<em>=> </em>
<em />
<em>=> 4x + 4 = 64</em>
<em>=> 4x = 64 - 4 = 60 </em>
<em>=> x = 60/4 = 15 (inches)</em>
So the length of an edge of the smaller square is 15 inches
Answer:
<span>=3<span>√6</span>−3<span>√5</span></span>
Explanation:
<span>3<span><span>√5</span>+<span>√6</span></span></span>
We rationalise the denominator by multiplying the expression by the conjugate of the denominator. <span><span>√5</span>−<span>√6</span></span>
<span><span>3⋅<span>(<span>√5</span>−<span>√6</span>)</span></span><span><span>(<span>√5</span>+<span>√6</span>)</span>⋅<span>(<span>√5</span>−<span>√6</span>)</span></span></span>
<span>=<span><span>3⋅<span>(<span>√5</span>)</span>+3⋅<span>(−<span>√6</span>)</span></span><span><span>(<span>√5</span>+<span>√6</span>)</span>⋅<span>(<span>√5</span>−<span>√6</span>)</span></span></span></span>
<span>=<span><span>3<span>√5</span>−3<span>√6</span></span><span><span>(<span>√5</span>+<span>√6</span>)</span>⋅<span>(<span>√5</span>−<span>√6</span>)</span></span></span></span>
<span>Applying identity
<span><span>(a+b)</span><span>(a−b)</span>=<span>a2</span>−<span>b2</span></span> to the denominator.</span>
<span>=<span><span>3<span>√5</span>−3<span>√6</span></span><span><span><span>(<span>√5</span>)</span>2</span>−<span><span>(<span>√6</span>)</span>2</span></span></span></span>
<span>=<span><span>3<span>√5</span>−3<span>√6</span></span><span>5−6</span></span></span>
<span>=<span><span>3<span>√5</span>−3<span>√6</span></span><span>−1</span></span></span>
<span>=−3<span>√5</span>+3<span>√6</span></span>
<span>=3<span>√6</span>−3<span>√<span>5
</span></span></span>
Answer:
There area 14 one cent stamps
Step-by-step explanation:
Let
x -----> the number of 1 cent stamps
y -----> the number of 8 cent stamps
z -----> the number of 12 cent stamps
we know that
0.01x+0.08y+0.12z=1.78 -------> equation A
x=y+4 ------> y=x-4 -----> equation B
x=2z -----> z=0.5x ------> equation C
substitute equation B and equation C in equation A and solve for x
0.01x+0.08(x-4)+0.12(0.5x)=1.78
0.01x+0.08x-0.32+0.06x=1.78
0.15x=1.78 +0.32
0.15x=2.10
x=14
therefore
There area 14 one cent stamps
Answer:
2 to the 20th power over 3 to the 12th power
Step-by-step explanation:
Numerator: base = 2. Power=5*4=20
Denominator :base 3 Power=3*4=12
