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coldgirl [10]
3 years ago
12

An airplane over the Pacific Ocean sights an atoll at an 7° angle of depression. If the

Mathematics
1 answer:
Bond [772]3 years ago
3 0
I believe the answer is 5.73
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How many ways are there to choose a committee of 3 people from a group of 5 people? A. 10 B. 12 C. 60 D. 70
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12 12 12 12 12 12 12 its 12

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3 years ago
Use the quadratic formula to find both solutions to the quadratic equation given below x^2+6x=27
docker41 [41]

Answer:

x=3 or x=−9

Step-by-step explanation:

Step 1: Subtract 27 from both sides.

x2+6x−27=27−27

x2+6x−27=0

Step 2: Factor left side of equation.

(x−3)(x+9)=0

Step 3: Set factors equal to 0.

x−3=0 or x+9=0

x=3 or x=−9

Answer:

x=3 or x=−9

7 0
3 years ago
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Zack bought a cost for 69.78. he paid with $100 bill and received 26.73 in change. how much was the sales tax.
pshichka [43]
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3 0
3 years ago
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Divide. <br> 3/5 \1/4<br><br> A. 3/20<br> B. 5/12<br> C. 4/9<br> D. 2 2/5
KIM [24]
Its letter A 3/20 i divided it


4 0
3 years ago
Could someone help me, please?
k0ka [10]

We can rewrite the expression under the radical as

\dfrac{81}{16}a^8b^{12}c^{16}=\left(\dfrac32a^2b^3c^4\right)^4

then taking the fourth root, we get

\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|

Why the absolute value? It's for the same reason that

\sqrt{x^2}=|x|

since both (-x)^2 and x^2 return the same number x^2, and |x| captures both possibilities. From here, we have

\left|\dfrac32a^2b^3c^4\right|=\left|\dfrac32\right|\left|a^2\right|\left|b^3\right|\left|c^4\right|

The absolute values disappear on all but the b term because all of \dfrac32, a^2 and c^4 are positive, while b^3 could potentially be negative. So we end up with

\dfrac32a^2\left|b^3\right|c^4=\dfrac32a^2|b|^3c^4

3 0
3 years ago
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