Answer:
We conclude that:
∠A = ∠ FEC
Step-by-step explanation:
Given
△ABD ≅ △EFC
To determine:
∠A =
As
△ABD ≅ △EFC
So the triangles △ABD and △EFC are congruent to each other.
- We know that congruent triangles have equal corresponding parts.
Please check the attached graph.
From the graph, it is clear that ∠A is correspondent to ∠E.
∠A = ∠E
From the attached figure, it is clear that:
∠F can also be denoted by ∠ FEC
as
∠A = ∠E
so
∠A = ∠ FEC
Therefore, we conclude that:
∠A = ∠ FEC
76, 84, 93, 67, 82, 87, & 76
The mean is just the middle number of the data set,
Start by rewriting the set in order from smallest to biggest:
67, 76, 76, 82, 84, 87, 93
Determine which is the number in the middle,
67, 76, 76, *82*, 84, 87, 93
So, in this case, the median is 82.
Answer:
(3,2)
Step-by-step explanation:
...................
Okay, here we have this:
Considering the provided function, we are going to calculate the requested one-side limits, so we obtain the following:
f(x)g(x) = 9x² + 10x - 16
<u>Step-by-step explanation:</u>
Step 1:
Given f(x) = 3x - 4 × 2 + 6x and g(x) = 5x + 2 × 2 - 3x
f(x) = 9x - 8
g(x) = 2x + 4
f(x)g(x) = (9x - 8)(2x + 4)
= 18x² + 36x - 16x -32
= 18x² + 20x - 32
= 9x² + 10x - 16
