Answer:
11/13
Step-by-step explanation:
3/13, 5/13, 7/13, 9/13, <u>11/13</u>
3/13
3/13 + 2/13 = 5/13
5/13 + 2/13 = 7/13
7/13 + 2/13 = 9/13
9/13 + 2/13 = 11/13
There are 72 boys. 7:6 = 84:?, divide 84 by 7, you get 12. Multiply 6 by 12 to get the answer.
Answer:
807.8 in^2
Step-by-step explanation:
The total area of the box is the sum of the areas of all faces of the box. The top, bottom, front, and back faces are rectangles 18 in long. The end faces each consist of a rectangle and a triangle. We can compute the sum of these like this:
The areas of top, bottom, front, and back add up to be 18 inches wide by the length that is the perimeter of the end: 2·5in +2·8 in + 9.6 in = 35.8 in. That lateral area is ...
(18 in)(35.6 in) = 640.8 in^2
The area of the triangle on each end is equivalent to the area of a rectangle half as high, so we can compute the area of each end as ...
(9.6 in)(8.7 in) = 83.52 in^2
Then the total area is the lateral area plus the area of the two ends:
640.8 in^2 + 2·83.52 in^2 = 807.84 in^2 ≈ 807.8 in^2
Answer:
9
Step-by-step explanation:
most accurate answer if tax was added it would be about 10 added to the fee when u do the math so the answer is 9
Hi there! Use the following identities below to help with your problem.

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

As we know, sec²θ = 1/cos²θ.

And thus,

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

Answer
- sinθ = -4sqrt(17)/17 or A choice.