For questions #6 & #8, you didn't complete them or provide all necessary things (such as description, data, or graph). 5 − ≤ 20 is not an inequality, an inequality should be something like 5 - x ≤ 20, but you didn't give anything like that in your question.
7. (-1,4), (5,2), we can calculate the slope. As x increases from -1 to 5, (increases by 6), the y-value decreases by 2. -2/6 = -1/3, the slope is -1/3. The slope is negative and the y-value decreases by a third of the amount the x-value changes.
9. C, because you can only hold at MOST 500, and larger watermelons is represented by 10x. I'm assuming you made an error in your question, you gave me the values of larger/smaller watermelons only, and your question asked for larger & medium and the options seem to suggest there's only larger/smaller. 10x + 3y <= 500 or <, smaller than or equal would be the better choice if available.
10. y = 2x + 10, because 2 is the slope as minutes increase by 1, inches increase by 2, and the 10 inches of sawdust are already there.
When you offer Questions #6 & #8's data, I'll gladly help you with it. The rest of the questions are correct and properly explained.
X = 110
110-108 = 2
27*2=54
Answer:
Growth function.
The number of students enrolled in 2014 is 1162.
Step-by-step explanation:
The number of students in the school in t years after 2002 can be modeled by the following function:
In which N(0) is the number of students in 2002 and r is the rate of change.
If 1+r>1, the function is a growth function.
If 1-r<1, the function is a decay function.
In 2002, there were 972 students enrolled at Oakview High School.
This means that 
Since then, the number of students has increased by 1.5% each year.
Increase, so r is positive. This means that 
Then
Growth function.
Find the number of students enrolled in 2014.
2014 is 2014-2002 = 12 years after 2002, so this is N(12).
The number of students enrolled in 2014 is 1162.
Answer:
14
Step-by-step explanation:
28=Diameter
Radius= D/2
=14
<span>the answer is b. π(10^3) – π(4^3)</span><span> </span>
