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harina [27]
3 years ago
10

I need help with number 23!! Please

Physics
1 answer:
Juliette [100K]3 years ago
3 0
Ah hah !  There's an easy way and a hard way to do this one.
If it's OK with you, I'm gonna do it the easy way, and not even
talk about the hard way !

First, let's look at a few things in this question.

-- "gravitational force between a planet and a mass"
    This is just a complicated way to say "How much does the mass weigh ?"
    That's what we have to find.

-- If we know the mass, how do we find the weight ?
   Multiply the mass by the acceleration of gravity there.
   Weight = (mass) x (gravity) .

-- Do we know the acceleration of gravity on this dark mysterious planet ?
    We do if we read the second line of the question !  
    It's right there ... 8.8 m/s² .

-- We know the mass.  We know gravity.  And we know that
    if you multiply them, you get the weight (forced of gravity).

I'm pretty sure that you can do the rest of the solution now.

weight = (mass) x (gravity)

Weight = (17 kg) x (8.8 m/s²)

Multiply them:

Weight = 149.6  kg-m/s²

That complicated-looking unit is the definition of a Newton !

So the weight is  149.6 Newtons.  That's the answer.  It's choice-A.
It's about 33.6 pounds.

When this mass is on the Earth, it weighs about 37.5 pounds.
But when it's on this planet, it only weighs about 33.6 pounds.
That's because gravity is less on this planet. (8.8 there, 9.8 on Earth)
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Coach ulcer paces the sidelines. Sarting at the 30 yd. line (A), he moves to the 10 yd. line (B), back to the 50 yd. line (C) an
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Answer:

See the answer below

Explanation:

<em>Average speed = total distance traveled/total time taken</em>

In order to determine the total distance traveled by the coach, consider the attached image.

Distance covered:

30 yd. line to 10 yd. line (A to B)= 20 yds

10 yd. line to 50 yd. line (B to C) = 40 yds

50 yd. line to 20 yd. line (C to D) = 30 yds

Total distance covered = 20 + 40 + 30 = 90 yds

Time taken = 200 seconds

Average Speed = 90/200 = <em>0.45 yd/s</em>

<em>Velocity = speed with direction</em>

Hence,

His Velocity = <em>0.45 yd/s to the left of his starting point.</em>

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3 years ago
Long term exposure to ___________ waves can cause sunburns and skin cancer. A) visible B) infrared C) gamma rays D) ultraviolet
Rudik [331]

Ultraviolet/UV radiation

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4 years ago
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The propeller on a boat motor is initially rotating at 8 revolutions per second. As the boat captain reduces the boat speed, the
I am Lyosha [343]

Answer: 5.77\ rps

Explanation:

Given

Initial angular velocity is \omega_i=8\ rps

rate of reduction \alpha=0.9 rev/s^2

after 17 revolution i.e. \theta =17\ rev

using \Rightarrow \omega_f^2-\omega_i^2=2\alpha\theta

Insert the values

\Rightarrow \omega_f^2=8^2-2\times (0.9)\times17\\\Rightarrow \omega_f^2=33.4\\\Rightarrow \omega_f=5.77\ rps

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Which one of the risk factors that influence you learn how may be most difficult to control as a young teen
nalin [4]
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3 years ago
I need help please someone !!!!! Would appreciate it
babymother [125]

Answer:

Yes, it would make it back up.

Explanation:

If it has 100,000 Joules of gravitational potential energy at the top of the hill, by the time the cart gets to the bottom, it will become PE = 0, KE = 90,000 since 10% of 100,000 is 10,000. The cart only requires 80,000J to climb back up so it should easily do so.

I didn't quite understand if the 10% energy loss is total, or every time it goes up or down, but it isn't a problem because 10% of 90,000 is 9,000, which means it would have 81,000J of energy on the way back up IF it loses energy due to friction on the way back up also.

The only physical law you need to prove this is the Law of Conservation of Energy: no energy is lost, only transformed; 10% of the energy becomes heat, the rest remains mechanical energy, which is the reason why the reasoning above works.

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