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tino4ka555 [31]
3 years ago
9

Can you check this and tell me if I anything wrong

Physics
1 answer:
posledela3 years ago
6 0
All correct except Moves large molecules which should be Diffusion
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A large fake cookie sliding on a horizontal surface isattached to one end of a horizontal spring with spring constantk = 425 N/m
omeli [17]

Answer:

Explanation:

spring constant k = 425 N/m

a ) At the point of equilibrium

restoring force = frictional force

= kx = 10 N

425 x = 10

x = 2.35 cm

b )

Work done by frictional force

= -10 x 2.35 x 10⁻² x 2  J ( Distance is twice of 2.35 cm )

= - 0.47 J

= Kinetic  energy remaining with the cookie  as it slides back through the position where the spring is unstretched .

= 425 - 0.47

= 424.53 J

=

4 0
3 years ago
An 80.0-gram sample of a gas was heated from 25 °C to 225 °C. During this process, 346 J of work was done by the system and its
Sidana [21]
Internal energy, U, is equal to the work done or by the system, plus the heat of the system: <span>ΔU=q+w
</span>in the question they tell you the work done by the system, and the internal energy:
8185 J= -346 J + q work is negative because it was done BY the system.
substitute in: <span>q=m∗Cp∗ΔT</span> and solve for <span>Cp</span><span>.
</span>
-------------------------------------
remember that <span>ΔT=<span>Tf</span>−<span>Ti
</span></span>
so the equation, really, is: <span>q=m∗Cp∗(<span>Tf</span>−<span>Ti</span>)</span><span>
------------------------------------------
</span>
<span>185J=−346J+[m∗Cp∗(<span>Tf</span>−<span>Ti</span>)]

</span>plug in the rest of your values and solve for <span><span>Cp</span></span>
4 0
3 years ago
PLEASE HELPP<br><br> just do the diagram
Natasha_Volkova [10]

Answer:the line away from the spacecraft should be straight down (perpendicular to it). Label this M. This is the force of the moon on the spacecraft. A minuscule line upward from the moon towards the spacecraft shows the force of the spacecraft on the moon. Should be directly below the spacecraft and pointed straight up at it.

Explanation:

4 0
2 years ago
A horizontal circular turntable rotates about its center at the uniform rate of 10.9 revolutions per minutes. Find the greatest
antiseptic1488 [7]

Answer:

6.03 m

Explanation:

First of all, let's convert the angular velocity from revolutions per minute to radians per second:

\omega = 10.9 \frac{rev}{min} \cdot \frac{2\pi rad/rev}{60 s/min}=1.14 rad/s

The frictional force on the block ranges from zero to a maximum value of

F=\mu mg

In order for the block to remain stuck on the turntable, the frictional force must be equal to the centripetal force, so we can write:

m\omega^2 r = \mu mg

where

m is the mass of the block

\omega is the angular velocity

r is the distance of the block from the centre

\mu = 0.8 is the coefficient of static friction

g = 9.8 m/s^2

Solving for r, we find:

r=\frac{\mu g}{\omega^2}=\frac{(0.8)(9.8)}{(1.14)^2}=6.03 m

8 0
3 years ago
According to Newton's second law of motion, the acceleration of an object is inversely proportional to which quantity?
vlabodo [156]
The answer is mass
So when the mass decreases the acceleration increases
6 0
3 years ago
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