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Bess [88]
3 years ago
6

A force of 120 N is exerted on a 40 kg container which sits on a floor. If the frictional force between floor and container is 8

0 N, what is the magnitude of the acceleration of the container?
Physics
1 answer:
harkovskaia [24]3 years ago
7 0

Answer:

Magnitude is 144N .

Explanation:

a²+b²=c²

120N²+80N²=c²

14400+6400=c²

\sqrt{20800}   =  \sqrt{c} ^{2}

144N=c

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Explanation:

The Coulomb's law states that the magnitude of each of the electric forces between two point-at-rest charges is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them:

F=\frac{kq_1q_2}{d^2}

In this case we have an electron (-e) and a proton (e), so:

F=-\frac{ke^2}{d^2}\\F=-\frac{8.99*10^9\frac{N\cdot m^2}{s^2}(1.6*10^{-19}C)^2}{(933*10^{-9}m)^2}\\F=-2.64*10^{-16}N

In this case, the electric force is negative, therefore, the force is repulsive and its magnitude is:

F=2.64*10^{-16}N

3 0
3 years ago
What will be the acceleration of a 40-kilogram object that is pushed with a net force of 80 newtons?
ratelena [41]
= 80 N/40 kg
= 2 m/s 2
4 0
3 years ago
Two forces (4N and 3N) pull your the left, while a 12N force pulls to the right. What is the net force
Lapatulllka [165]

Answer:

The answer is 11N to the right

Explanation:

Because 4N-3N= 1N

Therefore, 12N-1N=11N

The netforce is 11N to the right, because the greatest force is 12N to the right so it is more likely that the object is being pulled to the right.

8 0
3 years ago
A thermodynamic process occurs, and the entropy of a system decreases. What can be concluded about the entropy change of the env
stepladder [879]

Answer:

It stays the same.

Explanation:

Entropy of a system either increases or remains constant in any process, it never decreases.

6 0
4 years ago
hich of the following statements are true for magnetic force acting on a current-carrying wire in a uniform magnetic field?Check
leonid [27]

Explanation:

The magnetic force acting on a current carrying wire in a uniform magnetic field is given by :

F=I(L\times B)

or

F=ILB\ sin\theta

Where

\theta is the angle between length and the magnetic field

The magnetic force is perpendicular to both current and magnetic field. It is maximum when it is perpendicular to both current and magnetic field.

So, the correct options are :

  1. The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines.
  2. .The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field.
  3. The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current.
7 0
4 years ago
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