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kherson [118]
3 years ago
6

-g With what tension must a rope with length 2.50 m and mass 0.120 kg be stretched for transverse waves of frequency 40.0 Hz to

have a wavelength of 0.750 m?
Physics
1 answer:
Alex17521 [72]3 years ago
8 0

Answer:

43.2 N

Explanation:

\lambda = Wavelength = 0.75 m

f = Frequency = 40 Hz

m = Mass of string = 0.12 kg

L = Length of string = 2.5 m

\mu = Linear density = \dfrac{m}{L}

Velocity of wave is given by

v=\lambda f\\\Rightarrow v=0.75\times 40\\\Rightarrow v=30\ m/s

The tension in string is given by

T=v^2\mu\\\Rightarrow T=30^2\times \dfrac{0.12}{2.5}\\\Rightarrow T=43.2\ N

The tension in the string is 43.2 N

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Researchers want to see if college students are more committed to their fraternity after going through a hazardous hazing ritual
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College student's commitment

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(8c8p49) A 115g Frisbee is thrown from a point 1.00 m above the ground with a speed of 12.00 m/s. When it has reached a height o
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Answer:

The work done on the Frisbee is 1.36 J.

Explanation:

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Potassium is a crucial element for the healthy operation of the human body. Potassium occurs naturally in our environment and th
Mariulka [41]

Answer:

a) 0.0288 grams

b) 2.6*10^{-10} J/kg

Explanation:

Given that:

A typical human  body contains about 3.0 grams of Potassium per kilogram of body mass

The abundance  for the three isotopes are:

Potassium-39, Potassium-40, and Potassium-41 with abundances are 93.26%, 0.012% and 6.728% respectively.

a)

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0.012% × 240 grams

= 0.012/100 × 240 grams

= 0.0288 grams

b)

the effective dose (in Sieverts) per year due to Potassium-40 in an 80- kg body is calculate as follows:

First the Dose in (Gy) = \frac{energy \ absorbed }{mass \ of \ the \ body}

= \frac{1.10*10^6*1.6*10^{-14}}{80}

= 2.2*10^{-10} \ J/kg

Effective dose (Sv) = RBE × Dose in Gy

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Effective dose (Sv) = 2.6*10^{-10} J/kg

 

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3 years ago
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