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kirza4 [7]
3 years ago
5

A rock is dropped off a cliff and falls the first half of the distance to the ground in 2.0 seconds. how long will it take to fa

ll the second half?
Physics
1 answer:
son4ous [18]3 years ago
8 0

Answer:

The answer is 0.83 seconds.

Explanation:

The formula of free fall is following:

h=1/2*g*t^2

Where g=9.8 m/s^2 and t=2 seconds, the rock takes:

h=1/2*9.8*2^2=19.6

19.6 meters. This is the half distance of the cliff. The whole distance is 39.2 meters. So it takes:

39.2=1/2*9.8*t^2\\t^2=8\\t=2.83

2.83 second to fall down completely. The rock takes the second half of the cliff in 0.83 seconds

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Answer:

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b)  the magnitude of the torque on the dipole

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Explanation:

from coulomb's law

E = \frac{kq}{r^{2} }

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the expression of the electric field due to dipole at a distance r is

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where k = 1/4πε₀

F = Qqs/4πε₀r³

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τ = F sinθ × s

θ = 90°

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τ = F × r

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∴ τ = (Qqs/4πε₀r³) × r

τ = Qqs/4πε₀r²

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