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frozen [14]
3 years ago
15

The timing device in an automobile's intermittent wiper system is based on an RC time constant and utilizes a 0.520 µF capacitor

and a variable resistor. Over what range (in MΩ) must R be made to vary to achieve time constants from 2.50 to 19.0 s?
Physics
1 answer:
GarryVolchara [31]3 years ago
6 0

Answer:

Range of R is from 4.81MΩ to 36.54 MΩ

Explanation:

Capacitance(C) = 0.520 µF = 0.52 x 10^(-6) F

Time constant = from 2.5 to 19 seconds

In RC circuits, time constant is;

r = RC

Where R is the range (in MΩ)

And r is time constant

Thus,

R = r/c

So minimum range will be at 2.5seconds.

Thus; Rmin = 2.5/(0.52 x 10^(-6)) = 4.81 x 10^(6) Ω = 4.81MΩ

Rmax = 19/(0.52 x 10^(-6)) = 36.54 x 10^(6) Ω = 36.54 MΩ

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snow_lady [41]

Answer:

0.16 kgm/s

Explanation:

m_1 = Mass of pellet = 2 g

m_2 = Mass of golf ball = 45 g

u_1 = Initial Velocity of pellet  = 60 m/s

u_2 = Initial Velocity of golf ball = 0 m/s

v_1 = Final Velocity of pellet = 40 m/s

v_2 = Final Velocity of golf ball

In this system the linear momentum is conserved

m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\Rightarrow m_2v_2=m_1u_1+m_2u_2-m_1v_1\\\Rightarrow m_2v_2=0.002\times 60+0-0.002\times 40\\\Rightarrow m_2v_2=0.04

As the golf ball is being shot 4 times every second the momentum delivered to the golf ball each second is 4\times 0.04=0.16\ kgm/s

8 0
3 years ago
When the driver is disturbed by emotions, this manifests itself by_______ risk taking behavior.
Alborosie
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7 0
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If a black hole itself emits no radiation, what evidence do astronomers and physicists today have that the theory of black holes
AleksandrR [38]

Answer:

Einstein's general theory of relativity is the theory behind black holes has been tested with a wide range of experiments of which all confirm the predictions the theory makes. We cannot see black holes phenomena inside the event horizon, we do observe things outside this limit.

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6 0
3 years ago
An arrow strikes a target moving at 75 m/s and embeds itself 15 cm into the target. If the arrow stopped with constant accelerat
zhenek [66]

Answer:

Answer:

4 ms

Explanation:

initial velocity, u = 75 m/s

final velocity, v = 0

distance, s = 15 cm = 0.15 m

Let the acceleration is a and the time taken is t.

Use third equation of motion

v² = u² + 2 a s

0 = 75 x 75 - 2 a x 0.15

a = - 18750 m/s^2

Use first equation of motion

v = u + at

0 = 75 - 18750 x t

t = 4 x 10^-3 s

t = 4 ms

thus, the time taken is 4 ms.

Explanation:

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3 years ago
The established value for the speed of light in a vacuum is 299,792,458 m/s. What is the order-of-magnitude of this number?
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