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2 years ago

9

The car salesman tells you that the car can go from a stopped position to 60 miles per hour in 6 seconds. He is giving you the c

ar's rate of
velocity.

instantaneous speed.

acceleration.

distance.

2 answers:

Naddik [55]2 years ago

8 0

The answer is <span>acceleration.</span>

eimsori [14]2 years ago

6 0

The correct answer is C. Acceleration

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A very long half-cylinder of radius r carries a total current is uniformly distributed across the circumference. Determine the m

Rufina [12.5K]

The magnetic field along the central axis of the cylinder will be <em>determined </em>using the formula given that all parameters are known

$dBz=\frac{uoR^2di}{2r^3}$

<h3>Magnetic field </h3>

Generally, A magnetic field is also referred to as a vector field that shows the magnetic presence on electric charges and magnetic materials.

The formula for magnetic field is

Where

$u=4\pi*10^{-7H/M}$

Therefore, the magnetic field along the central axis of the cylinder will be determined using the formula given that all parameters are known

For more information on Magnets

brainly.com/question/7802337

8 0

1 year ago

An object of 4 cm length is placed at a distance of 18 cm in front of a convex mirror of radius of curvature 30 cm. Find the pos

erica [24]

Answer:

The position is 8.18cm from the mirror.

Nature is b=virtual

Size is 1.82cm

Explanation:

Note that for a convex mirror, the image distance and the focal length are negative;

Given

Object height H0 = 4cm

object distance u = 18cm

Radius of curvature R = 30cm

Since f = R/2

f = 30/2

f = -15cm

Recall that:

$\frac{1}{f} =\frac{1}{u}+ \frac{1}{v}\\\frac{1}{-15}=\frac{1}{18}+\frac{1}{v} \\\frac{1}{v} =\frac{1}{-15} -\frac{1}{18}\\ \frac{1}{v} = \frac{-18-15}{270}\\\frac{1}{v} = \frac{-33}{270}\\v=\frac{-270}{33}\\v=-8.18cm$

Since the image distance is negative, this shows that the image is a virtual image.

To get the size:

$\frac{H_1}{H_0}=\frac{v}{u}\\\frac{H_1}{4}=\frac{8.18}{18}\\18H_i=32.72\\H_i=\frac{32.72}{18}\\H_i= 1.82cm$

3 0

2 years ago

What is the impulse of a 1700 kg truck traveling at 22.5 m/s?

andrew-mc [135]

Impulse is just the product of mass and speed!

I = 1700 * 22.5 = 38,250 kg m/s

It does not have any special name for its units :(

3 0

2 years ago

garri49 [273]

Explanation:

(a) Hooke's law:

F = kx

7.50 N = k (0.0300 m)

k = 250 N/m

(b) Angular frequency:

ω = √(k/m)

ω = √((250 N/m) / (0.500 kg))

ω = 22.4 rad/s

Frequency:

f = ω / (2π)

f = 3.56 cycles/s

Period:

T = 1/f

T = 0.281 s

(c) EE = ½ kx²

EE = ½ (250 N/m) (0.0500 m)²

EE = 0.313 J

(d) A = 0.0500 m

(e) vmax = Aω

vmax = (0.0500 m) (22.4 rad/s)

vmax = 1.12 m/s

amax = Aω²

amax = (0.0500 m) (22.4 rad/s)²

amax = 25.0 m/s²

(f) x = A cos(ωt)

x = (0.0500 m) cos(22.4 rad/s × 0.500 s)

x = 0.00919 m

(g) v = dx/dt = -Aω sin(ωt)

v = -(0.0500 m) (22.4 rad/s) sin(22.4 rad/s × 0.500 s)

v = -1.10 m/s

a = dv/dt = -Aω² cos(ωt)

a = -(0.0500 m) (22.4 rad/s)² cos(22.4 rad/s × 0.500 s)

a = -4.59 m/s²

3 0

2 years ago

How can i prove the conservation of mechanical energy?

FinnZ [79.3K]

Answer:

We can also prove the conservation of mechanical energy of a freely falling body by the work-energy theorem, which states that change in kinetic energy of a body is equal to work done on it. i.e. W=ΔK. And ΔE=ΔK+ΔU. Hence the mechanical energy of the body is conserved

Explanation:

5 0

2 years ago