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3 years ago

True or false. electrons move in orbits in the same way plants orbit the sun

Physics

2 answers:

zalisa [80]3 years ago

7 0

One plants don't orbit the sun, the earth does.
two true if its saying plants orbit the sun

Len [333]3 years ago

4 0

This is false. Electrons do not orbit in the same way that planets orbit the sun. But they are similar since both fields behave the same way except that the Gravitational force is a long range force. T<span>he main difference is that electron orbits are oriented in all directions.</span>

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NASA is giving serious consideration to the concept of solar sailing. A solar sailcraft uses a large, low mass sail and the ener

Stella [2.4K]

Answer:

Reflective

Explanation:

The radiation pressure of the wave that totally absorbed is given by;

$P_{abs}= \frac{I}{C}$

and While the radiation pressure of the wave totally reflected is given by;

$P_{ref}= \frac{2I}{C}$

Now compare the two-equation you can clearly see that the pressure due to reflection is larger than absorption therefore the sail should be reflective.

6 0

3 years ago

In Example 2.7, we investigated a jet landing on an aircraft carrier. In a later maneuver, the jet comes in for a landing on sol

igor_vitrenko [27]

Answer:

a) 20 seconds

b) No.

Explanation:

t = Time taken for jet to stop

u = Initial velocity = 100 m/s (given in the question)

v = Final velocity = 0 (because the jet will stop at the end)

s = Displacement of the jet (Distance between the moment the jet touches the ground to the point the point it stops)

a = Acceleration = -5.00 m/s² (slowing down, so it is negative)

a) Equation of motion

$v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-100}{-5}\\\Rightarrow t=20\ s$

The time required for the plane to slow down from the moment it touches the ground is 20 seconds.

$s=ut+\frac{1}{2}at^2\\\Rightarrow s=100\times 20+\frac{1}{2}\times -5\times 20^2\\\Rightarrow s=1000\ m$

The distance it requires for the jet to stop is 1000 m so in a small tropical island airport where the runway is 0.800 km long the plane would not be able to land. The runway needs to be atleast 1000 m long here the runway on the island is 1000-800 = 200 m short.

5 0

3 years ago

The smallest detail visible with ground-based solar telescopes is about 1 arc second. How large a region (in km) does this repre

mestny [16]

Answer:

x = 727.5 km

Explanation:

With the conditions given using trigonometry, we can find the tangent

tan θ = CO / CA

With CO the opposite leg and CE is the adjacent leg which is the distance from the Tierral to Sun

D =150 10⁶ km (1000m / 1 km)

D = 150 10⁹ m.

We must take the given angle to radians.

1º = 3600 arc s

π rad = 180º

θ = 1 arc s (1º / 3600 s arc) (pi rad / 180º) =

θ = 4.85 10⁻⁶ rad

That angle is extremely small, so we can approximate the tangent to the angle

θ = x / D

x = θ D

x = 4.85 10-6 150 109

x = 727.5 103 m

x = 727.5 km

4 0

3 years ago

Can anyone pls answer this plss plss I'm not sure which one it is

lyudmila [28]

Answer:

a) wet marble , dry marble, newspaper, and towel

5 0

2 years ago

A flat coil of wire consisting of 15 turns, each with an area of 40 cm 2, is positioned perpendicularly to a uniform magnetic fi

zheka24 [161]

Answer:

0.54 A

Explanation:

Parameters given:

Number of turns, N = 15

Area of coil, A = 40 cm² = 0.004 m²

Change in magnetic field, ΔB = 5.1 - 1.5 = 3.6 T

Time interval, Δt = 2 secs

Resistance of the coil, R = 0.2 ohms

To get the magnitude of the current, we have to first find the magnitude of the EMF induced in the coil:

|V| = |(-N * ΔB * A) /Δt)

|V| = | (-15 * 3.6 * 0.004) / 2 |

|V| = 0.108 V

According to Ohm's law:

|V| = |I| * R

|I| = |V| / R

|I| = 0.108 / 0.2

|I| = 0.54 A

The magnitude of the current in the coil of wire is 0.54 A

6 0

3 years ago