Answer:
mu = 0.56
Explanation:
The friction force is calculated by taking into account the deceleration of the car in 25m. This can be calculated by using the following formula:

v: final speed = 0m/s (the car stops)
v_o: initial speed in the interval of interest = 60km/h 
     = 60(1000m)/(3600s) = 16.66m/s
x: distance = 25m
BY doing a the subject of the formula and replace the values of v, v_o and x you obtain:

with this value of a you calculate the friction force that makes this deceleration over the car. By using the Newton second's Law you obtain:

Furthermore, you use the relation between the friction force and the friction coefficient:

hence, the friction coefficient is 0.56
 
        
             
        
        
        
Answer:
The total displacement is 102 km  north of east.
 north of east.
Explanation:
We can treat this problem as a trigonometric one, so we need to calculate the total displacement on the north and east.

and

The total displacement is given by:

with an agle of:

 
        
             
        
        
        
Answer:
Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed
Unit: Pascal (Pa)
1Pa = 1N/m^2
 
        
             
        
        
        
Answer:
F =1490.9 N
Explanation:
given,
work done = 82 J
compression length = 0.220 m
for parallel combination

          = 2 k
work done




force = 
F = kx
F = 3388.43 ×0.22
F =745.45 N
the additional work done
final potential energy = 
                                     = 4 W = 328 J
the additional work = 328 - 82 = 255 J
 maximum force
F = k × 2x
F = 2×745.45
F =1490.9 N
                                    
 
        
             
        
        
        
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