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Ganezh [65]
4 years ago
15

True or false. electrons move in orbits in the same way plants orbit the sun

Physics
2 answers:
zalisa [80]4 years ago
7 0
One plants don't orbit the sun, the earth does.
two true if its saying plants orbit the sun
Len [333]4 years ago
4 0
This is false. Electrons do not orbit in the same way that planets orbit the sun. But they are similar since both fields behave the same way except that the Gravitational force is a long range force. T<span>he main difference is that electron orbits are oriented in all directions.</span>
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A force of 8,480 N is applied to a cart to accelerate it at a rate of 26.5 m/s2. What is the mass of the cart?
Anni [7]
F=ma
8480=26.5m
m=8480/26.5
m=320
The mass of the cart is 320kg.
8 0
3 years ago
Read 2 more answers
Object's velocity change
marshall27 [118]

the definition of acceleration in kinematics, allows to find that the correct answer is:

     2.  speed up  ( acceleration)

The kinematics study the movement of the body, the acceleration is defined as the change of the speed by the time in the interval

             a = Δv / t

Where the bold letters indicate vectors, a is the acceleration, v the velocity and t the time

Analyzing this expression we see that for there to be a change in velocity, there must be an acceleration of the body.

Let's analyze the different claims

1. True. If it is stopped and you start to move there is an acceleration, therefore there is a change in speed, but after you are moving the acceleration becomes zero and there is no change in speed

2. True. Whenever there is acceleration there is a change in speed

3. False. Moving slowly does not change the acceleration, therefore there is no change in speed

4. True. If you are moving and you stop at this moment there is an acceleration, therefore there is a change in speed, but after being stopped the acceleration is zero and there is no change in speed

5. False. If you change the direction at the instant of change there is an acceleration but after you go in the opposite direction there is not acceleration therefore there is no change in speed.

In conclusion using the definition of acceleration in kinematics, we can find the answer the condition for a change in velocity, the correct statement is:

     2.   speed up  ( acceleration)

Learn more here:  brainly.com/question/5063616

3 0
2 years ago
If a planet has 3 times the radius of the Earth, but has the same density as the Earth, what is the gravitational acceleration a
xz_007 [3.2K]

Answer:

The Gravitational Acceleration of the Big planet is G = 3g

where G is the gravitational acceleration of the Big Planet and g is the gravitational acceleration of the Earth

So, it becomes G = 3 x 9.8ms^{-2}

G = 29.4 ms^{-2}  

Explanation:

Let's start by calculating the <u>Density of the Earth</u> of mass m anad Radius r

We know that mass is density times the volume

ρ = \frac{m}{V}

m = ρV

we know the volume is V = \frac{4}{3} πr^{3} (please ignore the symbol of Pi)

m = ρ\frac{4}{3} πr^{3}

Calculating the <u>Density of Big Planet</u>

→For Big Planet we know that radius is 3-times the radius of Earth, that is 3r

M = ρ\frac{108}{3} π(r)^{3}    

So in conclusion, the mass of Earth and the mass of Big planet are related as M = 27m    

Now let's come to the Gravitational Force, we know that gravitational force is directly proportional to the mass of the body and inversely proportional to the radius.

→Suppose for Earth:  Mass = m, Radius = r  

For Big Planet:   Mass = M, Radius = R

\frac{m}{r^{2} } :  \frac{M}{R^{2} } = g : G

\frac{Gm}{r^{2} } =  \frac{gM}{R^{2} }

G =\frac{gMr^{2}}{mR^{2}}

→ Putting the value of R = 3r and M = 27m

G = \frac{g27mr^{2}}{m(3r)^{2}}

By cutting the terms, we get

G = 3g

value of g= 9.8ms^{-2}  

G = 3 x 9.8ms^{-2}  

G = 29.4 ms^{-2}  

5 0
4 years ago
A 0.03-kg bullet is fired with a horizontal velocity of 470 m/s and becomes embedded in block B which has a mass of 3 kg. After
Gala2k [10]

Answer with Explanation:

We are given that

Mass of bullet,m_1=0.03 kg

u_1=470 m/s

m_2=3 kg

\mu_k=0.2

m_3=30 kg

We have to find the velocity of the bullet and block B after the first impact and final velocity of the carrier.

According to law of conservation of momentum

m_1u_1=(m_1+m_2)v

0.03(470)=(0.03+3)v

v=\frac{0.03(470)}{(0.03+3)}=4.65 m/s

Hence, the velocity of the bullet and block B after the first impact=4.65 m/s

According to law of conservation of momentum

(m_1+m_2)v=(m_1+m_2+m_3)V

(0.03+3)\times 4.65=(0.03+3+30)V

V=\frac{(0.03+3)\times 4.65}{(0.03+3+30)}

V=0.43 m/s

3 0
4 years ago
Read 2 more answers
What are the three most influential variables that affect electrical force?
snow_tiger [21]
I know that the answer is 3 because 1+2 is 3
4 0
4 years ago
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