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KiRa [710]
3 years ago
14

HELP FAST I’LL MARK YOU BRAINLIEST What is the slope of a line perpendicular to the line whose equation is 6x+4y=72. Fully reduc

e your answer.
Mathematics
1 answer:
denis23 [38]3 years ago
4 0

Answer:

2/3

Step-by-step explanation:

6x + 4y = 72

-6x         -6x

4y = 72 - 6x

/4         /4

y = 18 - 6/4x

y = -6/4x + 18

perpidicular slope is the opposite reciprical of the original line:

-6/4 is the slope of the line above.

4/6  or 2/3 would be the desired slope

check:

the two slopes mutplied would equal -1

-6/4 x 2/3 = -12/12 = -1

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The answer as a ration is 3:7r
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If 1+1 = x - 7<br> What is the value of X?
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Find the value of w (u(2))
katrin [286]
<h3>Answer:  17</h3>

==================================================

Explanation:

We'll start things off by computing the inner function u(2)

Plug x = 2 into the u(x) function

u(x) = -x-1

u(2) = -2-1

u(2) = -3

This tells us that w(u(2)) is the same as w(-3). I replaced u(2) with -3.

We'll plug x = -3 into the w(x) function

w(x) = 2x^2-1

w(-3) = 2(-3)^2 - 1

w(-3) = 2(9) - 1

w(-3) = 18-1

w(-3) = 17

Therefore, w(u(2)) = 17

------------------------

Here's a slightly different approach:

Let's find what w(u(x)) is in general

w(x) = 2x^2 - 1

w(u(x)) = 2(u(x))^2 - 1

w(u(x)) = 2(-x-1)^2 - 1

Then we can plug in x = 2

w(u(x)) = 2(-x-1)^2 - 1

w(u(2)) = 2(-2-1)^2 - 1

w(u(2)) = 2(-3)^2 - 1

w(u(2)) = 2(9) - 1

w(u(2)) = 18 - 1

w(u(2)) = 17

3 0
3 years ago
What are the first 50 decimal numbers in pie 3.14159265 Then what?
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7 0
3 years ago
Read 2 more answers
3
Marianna [84]

The expression into a single logarithm is log[(x)^{10}][(2)^{30}]

Step-by-step explanation:

Let us revise some logarithmic rules

  • log(a)^{n}=nlog(a)
  • log(ab)=log(a)+log(b)
  • nlog(a)+mlog(b)=log[(a)^{n}][(b)^{m}]

∵ 10 log(x) + 5 log(64)

- At first re-write 10 log(x)

∴  10 log(x) = log(x)^{10}

- Then re-write 5 log(64)

∴  5 log(64) = log(64)^{5}

∴ 10 log(x) + 5 log(64) = log(x)^{10} + log(64)^{5}

- Use the 3rd rule above to make it single logarithm

∵ log(x)^{10} + log(64)^{5} = log[(x)^{10}][(64)^{5}]

∴ 10 log(x) + 5 log(64) = log[(x)^{10}][(64)^{5}]

∵ 64 = 2 × 2 × 2 × 2 × 2 × 2

∴ We can write 64 as 2^{6}

∴ (64)^{5}=(2^{6})^{5}

- Multiply the two powers of 2

∴ (64)^{5}=(2)^{30}

∴ 10 log(x) + 5 log(64) = log[(x)^{10}][(2)^{30}]

The expression into a single logarithm is log[(x)^{10}][(2)^{30}]

Learn more:

You can learn more about the logarithmic functions in brainly.com/question/11921476

#LearnwithBrainly

6 0
3 years ago
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