Answer: n the laboratory, the life time of a particle moving with speed 2.8 x 10^10 cm\s is found to be 2.5 x 10^-7. Calculate the proper life of the ...
Explanation:
Answer:
Explanation:
Given
For first case
launch angle 
at highest point 


For second case

at highest Point velocity is 

as there is no acceleration in x direction therefore horizontal velocity is same
Having said that,
mV + M0 = (m + M)v; where m = bullet mass, M = block mass, V = bullet velocity upon incoming, and v = the block and bullet velocity (ideal without losses) is the answer you are looking for. Thus, v = V(m/(m + M)) is what you want. m = Mb, M = Mw, and V = Vi.
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Answer:
4776.98 N is the minimum force to start the rise.
Explanation:
We can use the first Newton's law to find the minimum force to move the block.
So we will have:

Where:
- F is the force
- W(x) is the weight of the block in the x direction, W = mg*sin(15)
- F(f) is the static friction force (F(f) = μN), μ is the static friction coefficient 0.4.





Therefore 4776.98 N is the minimum force to move the block.
I hope it helps you!