How much work must be done to stop a 1075-kg car traveling at 115 km/h ? Express your answer to two significant figures and incl
1 answer:
Answer:
Work done on the car will be 548440.9463 J
Explanation:
We have given mass of the car m = 1075 kg
As the car finally stops so final velocity of the car
Initial velocity of car u = 115 km/hr
Work done is equal to change in kinetic energy
So work done
=
As the work done is negative so work is done on the car to stop it .
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Answer:
Ф,
Ф
Explanation:
Now find the components NxNxN_x and NyNyN_y of N⃗ N→N_vec in the tilted coordinate system of Part B. Express your answer in terms of the length of the vector NNN and the angle θθtheta, with the components separated by a comma.
Vectors are quantities that have both magnitude and direction while scalar quantities have only magnitude but no direction.
This a vector quantity
from the diagram the horizontal component of the length of the vector will be
Ф
the vertical component will be
Ф
this is in the opposite direction because the x can be extrapolated to the negative axis
Answer:
The specific question is not stated, however the general idea is given in the attached picture. The electric field in each region can be found by Gauss’ Law.
at r < R:
Since the solid sphere is conducting, the total charge Q is distributed over the surface, and the electric field inside the sphere is zero.
E = 0.
at R < r < 2R:
The electric field can be found by Gauss’ Law as in the attachment. The green pencil shows this exact region.
at 2R < r:
The electric field can again be found by Gauss’ Law, the blue pencil shows the calculations for this region.
Explanation:
Gauss’ Law is straightforward when applied to spheres. The area of the sphere is , and the enclosed charge is given in the question as Q for the inner sphere, and 2Q for the whole system.
