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Lana71 [14]
3 years ago
15

How much work must be done to stop a 1075-kg car traveling at 115 km/h ? Express your answer to two significant figures and incl

ude the appropriate units
Physics
1 answer:
jok3333 [9.3K]3 years ago
6 0

Answer:

Work done on the car will be 548440.9463 J

Explanation:

We have given mass of the car m = 1075 kg

As the car finally stops so final velocity of the car v_f=0m/sec

Initial velocity of car u = 115 km/hr =115\times \frac{5}{18}=31.943m/sec

Work done is equal to change in kinetic energy

So work done =\frac{1}{2}mv_f^2-\frac{1}{2}mv_i^2

==\frac{1}{2}m(v_f^2-v_i^2)=\frac{1}{2}\times 1075\times (0^2-31.943^2)=-548440.946J

As the work done is negative so work is done on the car to stop it .

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