How much work must be done to stop a 1075-kg car traveling at 115 km/h ? Express your answer to two significant figures and incl
1 answer:
Answer:
Work done on the car will be 548440.9463 J
Explanation:
We have given mass of the car m = 1075 kg
As the car finally stops so final velocity of the car
Initial velocity of car u = 115 km/hr
Work done is equal to change in kinetic energy
So work done
=
As the work done is negative so work is done on the car to stop it .
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Explanation:
For equilibrium, .
So, = 0
=
= 705.6 N
Also, for equilibrium = 0
= 0
or,
=
= 176.4 N
Thus, we can conclude that the tension in the first rope is 176.4 N.
Answer:
a) Δx = 11.6 m
b) t = 3.9 s
Explanation:
a)
- Since the snowmobile is moving at constant speed, and the drive force is 195 N, this means that thereis another force equal and opposite acting on it, according to Newton's 2nd Law, due to there is no acceleration present in the horizontal direction .
- This force is just the force of kinetic friction, and is equal to -195 N (assuming the positive direction as the direction of the movement).
- Once the drive force is shut off, the only force acting on the snowmobile remains the friction force.
- According Newton's 2nd Law, this force is causing a negative acceleration (actually slowing down the snowmobile) that can be found as follows:
- Assuming the friction force keeps constant, we can use the following kinematic equation in order to find the distance traveled under this acceleration before coming to an stop, as follows:
- Taking into account that vf=0, replacing by the given (v₀) and a from (1), we can solve for Δx, as follows:
b)
- We can find the time needed to come to an stop, applying the definition of acceleration, as follows:
- Since we have already said that the snowmobile comes to an stop, this means that vf = 0.
- Replacing a and v₀ as we did in (3), we can solve for Δt as follows: