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STatiana [176]
2 years ago
6

A horse runs counterclockwise (anticlockwise) around the circular track of radius m at a constant speed, starting at the marked

point. It completes one lap in three minutes. What is its coordinate after one minute
Physics
1 answer:
Bezzdna [24]2 years ago
7 0

The horse is present between 1st and 2nd quarter of the circular track of horse racing.

<h3>What is its coordinate after one minute?</h3>

The coordinates of horse after one minute is between 1st and 2nd quarter because the horse completes one lap in 3 minutes. We know that the horse completes half lap in 1.5 minutes so in one minute the horse is between 1st and 2nd quarter.

So we can conclude that the horse is present between 1st and 2nd quarter of the circular track of horse racing.

Learn more about speed here: brainly.com/question/4931057

#SPJ1

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This answer is true the earth always stays at one speed
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What is glacier flood?<br>​
posledela

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2 years ago
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A 0.68 kg squirrel is resting on a branch 8 meters above the ground. What is the gravitational potential energy of a squirrel? A
ANEK [815]

Answer:

The gravitational potential energy of a squirrel is 53.312 J.

Explanation:

We have,

Mass of a squirrel is 0.68 kg

It is placed at a height of 8 m above the ground.

It is required to find the gravitational potential energy of a squirrel. It is possessed by an object due to its position. Its formula is given by :

E=mgh\\\\E=0.68\times 9.8\times 8\\\\E=53.312\ J

So, the gravitational potential energy of a squirrel is 53.312 J.

7 0
3 years ago
Can someone help me with this question
Mademuasel [1]

Answer:

Net force: 20 N to the right

mass of the bag: 20.489 kg

acceleration:  0.976  m/s^2

Explanation:

Since the normal force and the weight are equal in magnitude but opposite in direction, they add up to zero in the vertical direction. In the horizontal direction, the 195 N tension to the right minus the 175 force of friction to the left render a net force towards the right of magnitude:

195 N - 175 N = 20 N

So net force on the bag is 20 N to the right.

The mass of the bag can be found using the value of the weight force: 201 N:

mass = Weight/g = 201 / 9.81 = 20.489 kg

and the acceleration of the bag can be found as the net force divided by the mass we just found:

acceleration = 20 N / 20.489 kg = 0.976  m/s^2

8 0
3 years ago
chuck wagon travels with a constant velocity of 0.5 mile/minutes. determine the total distance traveled by Chuck Wagon during 12
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Given:

Velocity: 0.5 mile/minute

Time: 12 minute

Now we know that speed and velocity have the same magnitude. Hence speed=velocity=0.5 mile/min

Substituting the given values in the above formula we get

Distance = 0.5 x 12= 6 miles

7 0
3 years ago
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