Answer:
539N
Explanation:
Parameters given:
Mass of person = 66kg
Mass of parachute = 4kg
Downward acceleration = 2.1 m/s²
The total force acting on the system is the sum of the force of gravity and the force due to air acting opposite gravity:
F = mg - F(a)
Where g = acceleration due to gravity
Force is given as:
F = ma
=> ma = mg - F(a)
=> F(a) = mg - ma
F(a) = m(g - a)
m is the mass of the entire sustem
m = 66 + 4 = 70kg
=> F(a) = 70(9.8 - 2.1)
F(a) = 70 * 7.7
F(a) = 539N
The upward force on the open parachute from the air is 539N
Answer: mg/Cosθ
Explanation:
Taking horizontal acceleration of wedge as 'a'
FCosΘ = FsinΘ
F = mass(m) × acceleration(a) = ma
For horizontal resolution g = 0
Therefore,
Horizontal = Vertical
maCosΘ = mgSinΘ
aCosΘ = gSinΘ
a = gSinΘ/CosΘ
Recall from trigonometry :
SinΘ/Cosθ = tanΘ
Therefore,
a = gtanΘ
Normal force acing on the wedge:
mgCosΘ + maSinΘ - - - - (y)
Substitute a = gtanΘ into (y)
mgCosΘ + mgtanΘsinΘ
tanΘ = sinΘ/cosΘ
mgCosΘ + mgsinΘ/cosΘsinΘ
mgCosΘ + mgsin^2Θ/cosΘ
Factorizing
mg(Cosθ + sin^2Θ/cosΘ)
Taking the L. C. M
mg[(Cos^2θ + sin^2Θ) /Cosθ]
Recall: Cos^2θ + sin^2Θ = 1
mg[ 1 /Cosθ]
mg/Cosθ
Answer:
<h2>10,000 kg</h2>
Explanation:
The mass of the train can be found by using the formula
k is the kinetic energy
v is the velocity
From the question we have
We have the final answer as
<h3>10,000 kg</h3>
Hope this helps you
Given :
Initial velocity , u = 0 m/s² .
To Find :
The acceleration of the cart.
Solution :
Since, acceleration is constant.
Using equation of motion :
Putting, t = 1 s and x = 4 m in above equation, we get :
Therefore, the acceleration of the cart is 8 m/s².