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Maurinko [17]
3 years ago
15

An atom or ion has the abbreviated electron configuration [kr]. Select the species that it could not be

Physics
1 answer:
Lera25 [3.4K]3 years ago
3 0

An atom or ion which does not have the same electronic configuration as the species [kr] is K+

The complete question is given below:

An atom or ion has the abbreviated electron configuration (Kr). Select the species that it could not A. Br" B. K+ C. Sr24 D. Rbt E. Se-

<h3>What is an atom?</h3>

An atom can be defined as the smallest particle of an element which can take part in a chemical reaction.

Some elements are

  • Monoatomic; eg: C
  • Diatomic; eg: O2
  • Triatomic and others
  • Polyatomic

So therefore, an atom or ion which does not have the same electronic configuration as the species [kr] is K+

Learn more about atoms or ions of elements:

brainly.com/question/6258301

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Rosa pours a cup of boiling water into a pot of room-temperature water. According to the second law of thermodynamics, what will
11111nata11111 [884]

<u>Thermal energy</u><u> from the room-temperature water will continuously flow to the boiling water.</u>

  • The second law states, in a straightforward manner, that heat cannot naturally go "uphill."
  • When a pan of boiling water and a pan of ice are in touch, the hot water cools and the ice melts and warms up.

<h3>THE FIRST LAW OF THERMODYNAMICS</h3>
  • Adiabatic Process - is a procedure that is carried out without the system's heat content changing.
  • Water is heated to a temperature of 1000C during the boiling process, making it an isothermal process. As steam, the excess heat leaves the system.

Learn more about first law of thermodynamics brainly.com/question/3808473

#SPJ4

8 0
2 years ago
A fisherman sitting on the end of a pier notices that 6 wave crests pass him in 3 seconds. What is the frequency of the waves?.
dalvyx [7]

Answer:

2 Hz

Explanation:

f = frequency

n = wave crest

t = time

f = n/t → f = 6/3 = 2

4 0
3 years ago
In _____, marketers determine price based on what consumers are willing to pay and then subtract desired margins to yield target
Alona [7]
I would have to say "a. cost-based pricing"
3 0
3 years ago
A 48.0-turn circular coil of radius 5.50 cm can be oriented in any direction in a uniform magnetic field having a magnitude of 0
Andrew [12]

Answer:

Explanation:

Given that,

Number of turn is 48

N=48

Radius is 4.8cm

r=0.048m

Magnetic Field

B=0.48T

Current in coil

i=23.3mA

i=0.233A

Maximum Torque?

Maximum torque occur at angle 90°

Torque is given as

τ = N•I•A•B•sinθ

Where N is number of turn =48

I is current in coil =0.233A

A is area of circular coil form

Area of a circle is given as

A=πr²

A=π×0.048²

A=0.007238m²

B is magnetic field =0.48T

Maximum torque occurs at 90°

τ = N•I•A•B•sinθ

τ=48×0.233×0.007238×0.48×Sin90

τ = 0.0389Nm

This torque is large enough to exert the coil

4 0
4 years ago
Read 2 more answers
1. What is the value of the acceleration that the car experiences? 2. What is the value of the change in velocity that the car e
tankabanditka [31]

Answer:

All the answers are solved and explained below.

Explanation:

Note: This questions lacks the initial and most necessary data to answer these following questions. I have found a related question. I will be considering that question to carry out the answers.

Question: A car with a mass of 1000 kg is at rest at a spotlight. when the light turns green, it is pushed by a net force of 2000 N for 10 s. (This was the information missing in this question).

Data Given:

m = 1000 kg

F = 2000N

t = 10s

Q1 Solution:

Acceleration = a = ?

F = ma

a = F/m

a = 2000/ 1000

a = 2 m/s^{2}

Q2: Solution:

Change in velocity = Δv = ?

acceleration = change in velocity / time

a = Δv/t

Δv = axt

Δv = 2 x 10

Δv = 20 m/s

Q3: Solution:

Impulse = I = ?

Impulse = Force x time

I = 2000 x 10

I = 20000 Ns

Q4: Solution:

Change in Momentum = Δp = ?

Δp = mΔv

Δp = 1000 x 20

Δp = 20000 Kgm/s

Q5: Solution:

Final velocity of the car at the end of 10 seconds = vf = ?

Δp = m x Δv

Δp = m x (vf-vi)

Δp = 1000 x (vf - 0 )

20000 = 1000 x vf

vf = 20000/1000

vf = 20 m/s

Q6: Solution:

Change in momentum the car experiences as it continues at this velocity?

Δp = ?

Δp = mΔv

Δp = m x (0)

Δp = 0

Q7: Solution:

Impulse = Change in momentum

Impulse = Δp

Implulse = 0

Q8: Solution:

Change in momentum = Δp = mΔv

Δp = m(vf-vi)

Δp = 1000 x (0-20)

Δp = -20000 kgm/s

Q9: Solution:

Impulse = Δp

Impulse = -20000 Ns

Q10: Solution:

Impulse = ?

Impulse = F x t

F = impulse/t

F = -20000/4s

F = -5000 N

Q11: Solution:

F = ma

a = ?

a = F/m

a = -5000/1000

a = -5m/s^{2}

6 0
3 years ago
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