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xxTIMURxx [149]
3 years ago
15

BIG POINT AND PLEASE ANSWER IT CORRECTLY

Mathematics
1 answer:
Yanka [14]3 years ago
5 0

Ax+By=C

y=-2x+8

Answer :2x+y=8

I think this is the answer.

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3 years ago
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B. 5 times the sum of 7 and 23​
Lynna [10]

5 (7 + 23)

(Use distributive property to solve)

1. 5*7 + 5*23

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Find the erea of the trapezoid.<br> show work for brainliest
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2 years ago
Consider this expression.
Harlamova29_29 [7]

Answer:

= -30x -36

Step-by-step explanation:

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= -6x - 24x - 36

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8 0
3 years ago
Find the simplified product b-5/2b x b^2+3b/b-5
White raven [17]

Answer:

The product \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}

Step-by-step explanation:

Given expression \frac{b-5}{2b} and \frac{b^2+3b}{b-5}

We have to find the product of  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}

   

Consider the given expression  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}

Multiply fractions, we have,

\frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d}

=\frac{\left(b-5\right)\left(b^2+3b\right)}{2b\left(b-5\right)}

Cancel common factor ( b - 5 )

we have, =\frac{b^2+3b}{2b}

Apply exponent rule,

\:a^{b+c}=a^ba^c

b^2=bb

=bb+3b=b(b+3)

=\frac{b\left(b+3\right)}{2b}

Cancel common factor b , we have,

=\frac{b+3}{2}

Thus, the product  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}

8 0
3 years ago
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