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3 years ago

Help me I am stuck find the quotient of 38.5 and 0.5 this is a question for my kid

Mathematics

2 answers:

Stella [2.4K]3 years ago

3 0

Answer:

I got 77

Step-by-step explanation:

38.5÷0.5=x

385÷5=x

x=77

vodka [1.7K]3 years ago

3 0

Answer:

Step-by-step explanation:

38x2 = 76

I did this because 0.5 is one half and you multiply it by 2 to get a whole number.

and you add 1 because there is 1 0.5 in 0.5

So the answer is 76+ 1 or 77

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At the beginning of each of her four years in college, Miranda took out a new Stafford loan. Each loan had a principal of $5,500

kaheart [24]

Answer:

D. $31,337.27

Step-by-step explanation:

We have that the initial amount of the loan is $5500.

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The rate of interest on the loan is 7.5% i.e. 0.075 and it was for the duration of 10 years.

Also, it is given that the loan was compounded annually.

We have the formula as,

$P=\frac{\frac{r}{n}\times PV}{1-(1+\frac{r}{n})^{-t\times n}}$

i.e. $PV=\frac{P\times [1-(1+\frac{r}{n})^{-t\times n}]}{\frac{r}{n}}$

Substituting the values, we get,

i.e. $PV=\frac{P\times [1-(1+\frac{0.075}{12})^{-10\times 12}]}{\frac{0.075}{12}}$

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i.e. $22000=\frac{P\times [1-(1.00625)^{-120}]}{0.00625}$

i.e. $22000=\frac{P\times [1-0.4735]}{0.00625}$

i.e. $22000=\frac{P\times 0.5265}{0.00625}$

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i.e. $P=\frac{137.5}{0.5265}$

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Thus, the total lifetime cost to pay of the loans compounded annually = 261.16 × 120 = $31,339.2

Hence, the total cost close to the answer is $31,337.27

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