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Sonja [21]
3 years ago
10

Solve the system of linear equations using elimination.

Mathematics
2 answers:
Vanyuwa [196]3 years ago
8 0

Answer:

Step-by-step explanation:

A

Irina18 [472]3 years ago
7 0

Answer:

X= -5, Y= 16/3

Step-by-step explanation:

Okay, first line dem up:

-5x+3y=-19

-x-3y=-11

We can add, so -5x plus -x is -6x Y gets cancelled out, and -19 plus -11 is -30. So our equation is:

-6x=-30

This means that x equals -5, and now we substitute the answer in an equation to find "y". I chose equation 2. So with x factored in, it's:

5-3y=-11

Subtract both sides by 5.

-3y=-16

And we get: y= 16/3

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57 1/2 as a decimal, Please help and Thanks
Nimfa-mama [501]
The answer is 57.5 because 57 represents a whole number and 1/2 equals .5 so 57.5.

People who answer the question will get a thank you!

4 0
3 years ago
What is the GCF of 28a^3 b and 16ab ? <br><br> A)4ab<br> B)4a3b<br> C)28ab<br> D)112a3b2
N76 [4]
28a⁴b: 2 · 2 · 7 · a · a · a · a · b
 16ab: 2 · 2 · 2 · 2 · a · b

GCF(28a⁴b, 16ab) = 4ab

The answer is A.
7 0
3 years ago
Make d the subject of the formula h=d/3+2
Pani-rosa [81]
Answer: D=3(h-2)

Explanation —>
8 0
2 years ago
A new security system needs to be evaluated in the airport. The probability of a person being a security hazard is 4%. At the ch
ivolga24 [154]

Answer:

(a) 0.9412

(b) 0.9996 ≈ 1

Step-by-step explanation:

Denote the events a follows:

P = a person passes the security system

H = a person is a security hazard

Given:

P (H) = 0.04,\ P(P^{c}|H^{c})=0.02\ and\ P(P|H)=0.01

Then,

P(H^{c})=1-P(H)=1-0.04=0.96\\P(P|H^{c})=1-P(P|H)=1-0.02=0.98\\

(a)

Compute the probability that a person passes the security system using the total probability rule as follows:

The total probability rule states that: P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})

The value of P (P) is:

P(P)=P(P|H)P(H)+P(P|H^{c})P(H^{c})\\=(0.01\times0.04)+(0.98\times0.96)\\=0.9412

Thus, the probability that a person passes the security system is 0.9412.

(b)

Compute the probability that a person who passes through the system is without any security problems as follows:

P(H^{c}|P)=\frac{P(P|H^{c})P(H^{c})}{P(P)} \\=\frac{0.98\times0.96}{0.9412} \\=0.9996\\\approx1

Thus, the probability that a person who passes through the system is without any security problems is approximately 1.

7 0
3 years ago
A fair coin is flipped 10 times and lands on heads 8 times. Provide a reason to justify the difference between the experimental
professor190 [17]

Answer:

THere will be 8 heads and 2 tails

Step-by-step explanation:

I don't know

5 0
3 years ago
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