Answer:
add 7 to 9 times k : 7+9k
c cubed minus the product of 5 and q plus 4 :
twice r plus 7 is equal to 45 minus r : 2r+7=45-r
Product of h and 4 is subtracted from one-fifth of x is 35 :(h*4) - 1/5*x
one third of the difference bewteen 6 and p is added to 8 : (6-p)+8
The next three terms of sequence are 65, 129 and 257
<em><u>Solution:</u></em>
<em><u>Given sequence is:</u></em>
2, 3, 5, 9, 17, 33
We have to find the next three terms in sequence
<em><u>Let us find the logic used in this sequence</u></em>
Thus the sequence is increasing by 2 raised to power 0, 1, 2 and so on
<em><u>Thus the next three terms are found by:</u></em>
Thus the next three terms of sequence are 65, 129 and 257
