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Bumek [7]
3 years ago
10

What is 0.4(5+2x)-0.5=3(0.3x+0.7) I've solved this but I'm not sure I got the right answer

Mathematics
2 answers:
iragen [17]3 years ago
8 0
0.4(5+2x)-0.5=3(0.3x+0.7)
2+0.8x-0.5=0.9x+2.1
0.8x-0.9x=2.1-2+0.5
-0.1x=2.5
x=-25
BlackZzzverrR [31]3 years ago
5 0
If you have a graphing calculator one way to know you are right is put the left side in Y1 and the right side in Y2 then hit 2nd trace and intersection then find the intersection and the X value is your answer. If you don't have a graphing calculator then I'm sorry
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Which pair of angles are supplementary angles
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Hope this Helps!
4 0
3 years ago
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The sum of the cube of a number and 12
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3 years ago
Factorise fully 77x-33x^2
lesya [120]

Answer:

11x(7 - 3x)

Step-by-step explanation:

77x - 33x² ← factor out 11x from each term

= 11x(7 - 3x)

7 0
2 years ago
Rewrite x2 − 6x + 7 = 0 in the form (x − a)2 = b, where a and b are integers, to determine the a and b values.
Setler79 [48]

Answer:

Therefore values of a and b are

a=3\ and\ b = 2

Step-by-step explanation:

Rewrite x^{2}-6x+7=0 in the form

(x-a)^{2}=b

where a and b are integers,

To Find:

a = ?

b = ?

Solution:

x^{2}-6x+7=0 ..............Given

Which can be written as

x^{2}-6x=-7

(\frac{1}{2} coefficient\ of\ x)^{2}=(\frac{1}{2}\times -6)^{2}=9

Adding half coefficient of X square on both the side we get

x^{2}-6x+9=-7+9=2 ...................( 1 )

By identity we have (A - B)² =A² - 2AB + B²

Therefore,

x^{2}-6x+9=x^{2}-2\times 3\times x+3^{2}=(x-3)^{2}

Substituting in equation 1 we get

(x-3)^{2}=2

Which is in the form of

(x-a)^{2}=b

On comparing we get

a = 3 and b = 2

Therefore values of a and b are

a=3\ and\ b = 2

4 0
3 years ago
Why did j ernest wilkins jr was the first to do something significant in math
Nuetrik [128]

Answer:

guess hes just smart

Step-by-step explanation:

6 0
2 years ago
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