Answer:
vf = 14.2176 m/s
Explanation:
Given
m = 4 Kg
viy = 7.00 ĵ m/s
Fx = 11.0 î N
t = 4.5 s
vf = ?
Using the Impulse - Momentum Theorem, we have
F*Δt = m*Δv ⇒ F*Δt = m*(vf - vi)
⇒ vf = (F*Δt + m*vi) / m
⇒ vf = (F*Δt + m*vi) / m
For <em>x-component</em>
⇒ vfx = (Fx*Δt + m*vix) / m = (11 N*4.5 s + 4 Kg*0 m/s) / (4 Kg)
⇒ vfx = 12.375 î m/s
For <em>y-component</em>
⇒ vfy = (Fy*Δt + m*viy) / m = (0 N*4.5 s + 4 Kg*7 m/s) / (4 Kg)
⇒ vfy = 7 ĵ m/s
Finally:
vf = √(vfx² + vfy²)
⇒ vf = √((12.375 m/s)² + (7 m/s)²)
⇒ vf = 14.2176 m/s
Answer: 4.2817 × 10^14 s^-1
Explanation:
The term "wave speed" is described as the distance covered by a wave in specific time duration. The wave speed (v) can be mathematically expressed as:
v=fλ
Where;
F= frequency which is the number of waves that pass a fixed point per unit time and it is also the number of cycles or vibrations undergone during pet unit of time by a body in periodic motion
λ= wavelength which is the distance between successive crests of a wave.
Given the data,
Wavelength λ= 7×10^-7m
Speed of light c= 2.99792 × 10^8 m/s
Frequency of visible light can be given as:
Frequency= speed of light/wavelength
Frequency = (2.99792 × 10^8 m/s) / (7×10^-7m)
Frequency= 4.2817 × 10^14 s^-1
Therefore, the frequency of the light wave is 4.2817 × 10^14 s^-1
Answer:
4 cm/s².
Explanation:
From the question given above, the following data were obtained from it:
Initial velocity (u) = 0 cm/s
Final velocity (v) = 40 cm/s
Time (t) = 10 s
Acceleration (a) =?
Acceleration is simply defined as the rate of change of velocity with time. Mathematically, it is expressed as follow:
Acceleration (a) = Change in velocity /time
Acceleration (a) = [final velocity (v) – initial velocity (u)] /time (t)
a = (v – u) /t
With the above formula, we can obtain the acceleration of the ball as follow:
Initial velocity (u) = 0 cm/s
Final velocity (v) = 40 cm/s
Time (t) = 10 s
Acceleration (a) =?
a = (v – u) /t
a = (40 – 0) / 10
a = 40/10
a = 4 cm/s²
Therefore, the acceleration of the ball is 4 cm/s²
If Ashton slips off the spinning fan, it takes a path that is tangential to the circle at any point.
<h3>What is circular motion?</h3>
Circular motion refers to motion that takes place along a circular path. We know that a circular motion has the formula;
v = 2πrf
Where;
r = speed
r = radius
f = frequency
Hence;
v = 2 × 3.142 × 0.8 × 1.2
v = 6.03 ms-1
If Ashton slips off the spinning fan, it takes a path that is tangential to the circle at any point.
Learn more about circular motion: brainly.com/question/2285236
To solve this problem it is necessary to apply the concepts related to Energy Carried by Electromagnetic Waves.
The energy calculated per unit area per unit of time that crosses a plane perpendicular to the wave is called from the theory as energy flow and is usually denoted by the letter S.
Its calculation can be developed by dividing the energy by the area in the time interval, that is:
Where,
Speed of light
E = Electric field
Vacuum permittivity
From the statement we are given the value of the electric field that is 100V / m, therefore:
Therefore the instantaneous rate of energy flow for this wave is
