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Taya2010 [7]
3 years ago
6

The moon doesn't fall to earth because of it's friction?​

Physics
2 answers:
otez555 [7]3 years ago
6 0

Answer:

I think No since the gravitational force of earth is not eneogh to pull moon to it

TiliK225 [7]3 years ago
4 0

Answer:

The Moon does not fall towards Earth right now because Earth rotates itself. The energy from the Earth's own rotation around its axis is gradually tranferred into energy of the Moon's orbital motion. That's why the Earth's rotating speed decreases but the distance to the Moon increases.

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Which of the following molecules found within the cell membrane is thought to be involved in cell self-recognition? a. carbohydr
Nadusha1986 [10]

Answer:

Lipids

Explanation:

Membrane mostly considered largely of lipid  bilayer. It is the double called phospholipids. These glycolipids contains the chain of fatty acids. These fatty acids determines that whether the sheet of membrane is formed around the vesicles or not.

Lipids that provide a liquid to the membrane cells. The consistency of liquid appears as the light oil. It consists of fatty acid chain that includes many fatty acid molecules for example oxygen that permeate from the membrane. These fatty acids repels large molecules fatty acids such as sugar, electrical charged ions etc.

6 0
3 years ago
The deflection plates in an oscilloscope are 10 cm by 2 cm with a gap distance of 1 mm. A 100 volt potential difference is sudde
Afina-wow [57]

Answer:Resistor-Capacitor (RC) circuits, when driven by a voltage/current source, display a type of time-dependent charging or discharging since the charge from the capacitor goes through the resistor. When considering a discharging phase, the time-dependent voltage takes the form

Explanation:

Vt = Voe^-t/RC

Vt equal time dependent voltage

R is the resistance

C is the capacitance of the oscilloscope

Given

Area of capacitor equal to 0.1 * 0.002m

Distance between plates equal 1/1000 = 0.0001m

Vo = 100v supply voltage

Resistance R =:1000ohms

Vt time dependent voltage = 50V

To find capacitance C = Eo(A/d)

C = (8.85 * 10^-12)* (0.002/0.001)

C= 1.77 * 10^-11

Solving the equation Vt = Voe^-t/RC

t = 0.6931RC

t = 0.6931(1000)(1.77*10^-11)

t = 1.2*10^-9

t = 1.2ns

It will take the oscilloscope 1.2ns to reach 50V

8 0
3 years ago
How fast must a 1000 kg car be moving to have a kinetic energy of 2.0×10^5j​
ankoles [38]

Answer:

E=0.5 m v^2

2*10^-5 = 0.5 1000*v^2

4*10^-5=1000v^2

4*10^-8=v^2

2*10^-4 =v

7 0
3 years ago
A turtle and a rabbit are in a 150 meter race. The rabbit decides to give the turtle a 1 minute head start. The turtle moves at
yan [13]

Answer:

a) s_{T} = 30\,m, b) t = 5\,min, c) \Delta t = 6.667\,s, d) \Delta s_{R} = 33.333\,m, e) t' = 11.667\,s, f) The rabbit won the race.

Explanation:

a) As turtle moves at constant speed, its position is determined by the following formula:

s_{T} = v_{T}\cdot t

Where:

t - Time, measured in seconds.

v_{T} - Velocity of the turtle, measured in meters per second.

s_{T} - Position of the turtle, measured in meters.

Then, the position of the turtle when the rabbit starts to run is:

s_{T} = \left(0.5\,\frac{m}{s} \right)\cdot (60\,s)

s_{T} = 30\,m

The position of the turtle when the rabbit starts to run is 30 meters.

b) The time needed for the turtle to finish the race is:

t = \frac{s_{T}}{v_{T}}

t = \frac{150\,m}{0.5\,\frac{m}{s} }

t = 300\,s

t = 5\,min

The time needed for the turtle to finish the race is 5 minutes.

c) As rabbit experiments a constant acceleration until maximum velocity is reached and moves at constant speed afterwards, the time required to reach such speed is:

v_{R} = v_{o,R} + a_{R}\cdot \Delta t

Where:

v_{R} - Final velocity of the rabbit, measured in meters per second.

v_{o,R} - Initial velocity of the rabbit, measured in meters per second.

a_{R} - Acceleration of the rabbit, measured in \frac{m}{s^{2}}.

\Delta t - Running time, measured in second.

\Delta t = \frac{v_{R}-v_{o,R}}{a_{R}}

\Delta t = \frac{10\,\frac{m}{s}-0\,\frac{m}{s}}{1.50\,\frac{m}{s^{2}} }

\Delta t = 6.667\,s

The time taken by the rabbit to reach maximum speed is 6.667 s.

d) On the other hand, the position reached by the rabbit when maximum speed is reached is determined by the following equation of motion:

v_{R}^{2} = v_{o,R}^{2} + 2\cdot a_{R}\cdot \Delta s_{R}

\Delta s_{R} = \frac{v_{R}^{2}-v_{o,R}^{2}}{2\cdot a_{R}}

\Delta s_{R} = \frac{v_{R}^{2}-v_{o,R}^{2}}{2\cdot a_{R}}

Where \Delta s_{R} is the travelled distance of the rabbit from rest to maximum speed.

\Delta s_{R} = \frac{\left(10\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}}{2\cdot \left(1.50\,\frac{m}{s^{2}} \right)}

\Delta s_{R} = 33.333\,m

The distance travelled by the rabbit from rest to maximum speed is 33.333 meters.

e) The time required for the rabbit to finish the race can be determined by the following expression:

t' = \frac{\Delta s_{R}}{v_{R}}

t' = \frac{150\,m-33.333\,m}{10\,\frac{m}{s} }

t' = 11.667\,s

The time required for the rabbit from rest to maximum speed is 11.667 seconds.

f) The animal with the lowest time wins the race. Now, each running time is determined:

Turtle:

t_{T} = 300\,s

Rabbit:

t_{R} = 60\,s + 6.667\,s + 11.667\,s

t_{R} = 78.334\,s

The rabbit won the race as t_{R} < t_{T}.

7 0
3 years ago
What happens when the data in an investigation does not support the origanal hypothesis
alexgriva [62]

Answer: The scientist gives up and starts an investigation on a new topic.

Explanation:

The data is altered so that it supports the original hypothesized. The data is then altered so that it supports the original hypothesis.

5 0
3 years ago
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