Answer:
To identify the electron transition that has the highest frequency in the hydrogen atom.Answer: The frequency of light produced by electron transition is highest among the given electron transition, therefore, the option (a) is correct.Explanation:The energy of emitted light by the electron transition is given as: is the energy of the initial level. is the energy of the final level.The energy difference for the electron transition is highest among given electronic transition.The energy of the light is given as:Here, is the plank’s constant. is the frequency of the light.The energy of the light is directly proportional to the frequency of the light.Therefore the frequency of light by the electron transition is highest among given electronic transition.
Explanation:
Answer:
6.45×10¯²⁶ J
Explanation:
From the question given above, the following data were obtained:
Frequency (f) = 97.3 MHz
Energy (E) =?
Next, we shall convert 97.3 MHz to Hz. This can be obtained as follow:
1 MHz = 1×10⁶ Hz
Therefore,
97.3 MHz = 97.3 MHz × 1×10⁶ Hz / 1 MHz
97.3 MHz = 9.73×10⁷ Hz
Thus, 97.3 MHz is equivalent to 9.73×10⁷ Hz.
Finally, we shall determine the energy at which the frequency is broadcasting. This can be obtained as follow:
Frequency (f) = 9.73×10⁷ Hz
Planck's constant (h) = 6.63×10¯³⁴ Js
Energy (E) =?
E = hf
E = 6.63×10¯³⁴ × 9.73×10⁷
E = 6.45×10¯²⁶ J
Therefore, the energy at which the frequency is broadcasting is 6.45×10¯²⁶ J
Answer:
Explanation:
the unit of work is derived unit because joule is defined the work done by the force aftab 1 newton causing the displacement of one metre something newton metre(n-m) is also used to measuring work
