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Assoli18 [71]
3 years ago
8

Help<3

Chemistry
1 answer:
olga2289 [7]3 years ago
5 0

Answer:

D. weight

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EleoNora [17]

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2.) C

3.) A

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7 0
4 years ago
A. yanlız 1<br>b. yanlız 3<br>c. 1 ve 3<br>d. 1 .2 ve 3<br><br><br><br>acil lütfen. tessekurler:)​
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iki kesinlikle doğrudur kolay gelsin

7 0
3 years ago
If there are 40 mol of NBr3 and 48 mol of NaOH, what is the excess reactant?
Nata [24]

Answer:

The correct answer is option B.

Explanation:

3NaOH+2NBr_3\rightarrow 3HOBr+3NaBr+N_2

Moles of NBr_3 = 40 mol

Moles of NaOH = 48 mol

According to reaction, 3 moles of NaOH reacts with 2 moles NBr_3

Then ,48 moles of NaOH will reacts with:

\frac{2}{3}\times 48 mol=32 mol of NBr_3

Then ,40 moles of NaBr_3 will reacts with:

\frac{3}{2}\times 40 mol=60 mol of NaOH

As we can see that 48 moles of sodium will completey react with 32 moles of nitrogen tribromide.

Moles left after reaction = 40 mol - 32 mol = 8 mol

Hence, the NBr_3 is an excessive reagent.

6 0
3 years ago
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heterogenous mixture

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According to Dalton's atomic theory
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