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Igoryamba
3 years ago
5

C2H6 O2 CO2 + H2O What reaction is it?

Chemistry
1 answer:
leonid [27]3 years ago
7 0

Answer:

COMBUSTION REACTION

Explanation:

The given reaction is a combustion reaction since the reactant is a hydrocarbon and it is burnt in the presence of oxygen. This produces carbon dioxide and water molecules

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The change from a liquid phase to a gaseous phase occurs when the vapor pressure of the liquid is equal to the atmospheric pressure exerted on the liquid.

Explanation:

Boiling is a physical change and molecules are not chemically altered during the process.

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3 years ago
When the concentrations of CH 3 Br and NaOH are both 0.100 M, the rate of the reaction is 0.0030 M/s. What is the rate of the re
mash [69]

Answer : The rate of the reaction if the concentration of CH_3Br is doubled is, 0.006 M/s

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The balanced equations will be:

CH_3Br+NaOH\rightarrow CH_3OH+NaBr

In this reaction, CH_3Br and NaOH are the reactants.

The rate law expression for the reaction is:

\text{Rate}=k[CH_3Br][NaOH]

As we are given that:

[CH_3Br] = concentration of CH_3Br = 0.100 M

[NaOH] = concentration of NaOH = 0.100 M

Rate = 0.0030 M/s

Now put all the given values in the above expression, we get:

0.0030M/s=k\times (0.100M)\times (0.100M)

k=0.3M^{-1}s^{-1}

Now we have to calculate the rate of the reaction if the concentration of CH_3Br is doubled.

\text{Rate}=k[CH_3Br][NaOH]

\text{Rate}=(0.3M^{-1}s^{-1})\times (2\times 0.100M)\times (0.100M)

\text{Rate}=0.006M/s

Thus, the rate of the reaction if the concentration of CH_3Br is doubled is, 0.006 M/s

3 0
4 years ago
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