I think 1.00 mol sorry if I’m wrong
Answer:
C₂ = 0.149 M
Explanation:
Given data:
Initial concentration = 0.407 M
Initial volume = 2.56 L
Final volume = 7.005 L
Final concentration = ?
Solution:
Formula:
C₁V₁ = C₂V₂
C₁ = Initial concentration
V₁ = Initial volume
C₂ = Final concentration
V₂ =Final volume
Now we will put the values.
0.407 M × 2.56 L = C₂ × 7.005 L
1.042 = C₂ × 7.005 L
C₂ = 1.042 M.L / 7.005 L
C₂ = 0.149 M
Protons goes in the blank. the word can be used for both.
Answer:
A. 3-chloro-1-methylcyclobutane.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to infer that the name of this compound is A. 3-chloro-1-methylcyclobutane because of the fact that the parent chain is a cyclobutane which starts by the methyl radical as it has the priority over the chlorine radical which is actually named first at the third carbon (clockwise).
Therefore the name is given in A, accordingly to the IUPAC rules of nomenclature.
Regards!