Answer:
357 g of the transition metal are present in 630 grams of the compound of the transition metal and iodine
Explanation:
In any sample of the compound, the percentage by mass of the transition metal is 56.7%. This means that for a 100 g sample of the compound, 56.7 g is the metal while the remaining mass, 43.3 g is iodine.
Given mass of sample compound = 630 g
Calculating the mass of iodine present involves multiplying the percentage by mass composition of the metal by the mass of the given sample;
56.7 % = 56.7/100 = 0.567
Mass of transition metal = 0.567 * 630 = 357.21 g
Therefore, the mass of the transition metal present in 630 g of the compound is approximately 357 g
<span>The equation that represents the process of photosynthesis
is: </span>
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</span>
<span>6CO2+12H2O+light->C6H12O6+6O2+6H2O</span>
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<span>Photosynthesis is the
process in plants to make their food. This involves the use carbon dioxide to
react with water and make sugar or glucose as the main product and oxygen as a
by-product. Since we are not given the mass of CO2 in this problem, we assume that we have 1 g of CO2 available. We calculate as follows:</span>
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</span>
<span>1 g CO2 ( 1 mol CO2 / 44.01 g CO2 ) ( 12 mol H2O / 6 mol CO2 ) ( 18.02 g / 1 mol ) = 0.82 g of H2O is needed</span>
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</span>
However, if the amount given of CO2 is not one gram, then you can simply change the starting value in the calculation and solve for the mass of water needed.
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Magnets have batteries and the batteries make the magnets work it depends on which way the batteries are facing or if not im sorry and i hope this helped
<span>Where is most of the high-level waste from nuclear reactors stored?
</span><span>the ocean</span>
It is called Condensation
