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Bad White [126]
3 years ago
14

grapevine trimming and other aromatics can be wrapped in aluminum foil with a few holes poked in it to?

Chemistry
1 answer:
Juli2301 [7.4K]3 years ago
7 0
I need a little more context but I believe you are correct
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Based on the three formulas shown, use one of them to solve for the purple yellow and red box and explain how you did it.
zysi [14]

P = 11.133 atm (purple)

T = -236.733 °C(yellow)

n = 0.174 mol(red)

<h3>Further explanation  </h3>

Some of the laws regarding gas, can apply to ideal gas (volume expansion does not occur when the gas is heated),:  

  • Boyle's law at constant T, P = 1 / V  
  • Charles's law, at constant P, V = T  
  • Avogadro's law, at constant P and T, V = n  

So that the three laws can be combined into a single gas equation, the ideal gas equation  

In general, the gas equation can be written  

\large {\boxed {\bold {PV = nRT}}}

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

To choose the formula used, we refer to the data provided

Because the data provided are temperature, pressure, volume and moles, than we use the formula PV = nRT

  • Purple box

T= 10 +273.15 = 373.15 K

V=5.5 L

n=2 mol

\tt P=\dfrac{nRT}{V}\\\\P=\dfrac{2\times 0.08205\times 373.15}{5.5}\\\\P=11.133~atm

  • Yellow box

V=8.3 L

P=1.8 atm

n=5 mol

\tt T=\dfrac{PV}{nR}\\\\T=\dfrac{1.8\times 8.3}{5\times 0.08205}\\\\T=36.42~K=-236.733^oC

  • Red box

T = 12 + 273.15 = 285.15 K

V=3.4 L

P=1.2 atm

\tt n=\dfrac{PV}{RT}\\\\n=\dfrac{1.2\times 3.4}{0.08205\times 285.15}\\\\n=0.174~mol

3 0
3 years ago
A naturally occurring oil co-distills with water to produce an oil/water distillate that is 20% oil by weight. If the molecular
Gelneren [198K]

Answer:

Explanation:

Partial pressure of oil = mole fraction of oil x total pressure

mole fraction of oil = mole of oil / mole of water + mole of oil

= mole of oil = mass of oil / molecular weight of oil

= 20 / 100 = .2

mole of water = 80 / 18

= 4.444

mole fraction of oil =  .2 / .2 + 4.444

= .2 / 4.644

Partial pressure of oil = mole fraction of oil x total pressure

= (.2 / 4.644 ) x 760 mm

= 32.73 mm Hg .

3 0
3 years ago
Hexane and octane are mixed to form a 45 mol% hexane solution at 25 deg C. The densities of hexane and octane are 0.655 g/cm3 an
avanturin [10]

Answer:

The required volume of hexane is 0.66245 Liters.

Explanation:

Volume of octane = v=1.0 L=1000 cm^3

Density of octane= d = 0.703 g/cm^3

Mass of octane ,m= d\times v=0.703 g/cm^3\times 1000 cm^3=703 g

Moles of octane =\frac{m}{114 g/mol}=\frac{703 g}{114 g/mol}=6.166 mol

Mole percentage of Hexane = 45%

Mole percentage of octane = 100% - 45% = 55%

55\%=\frac{6.166 mol}{\text{Total moles}}\times 100

Total moles = 11.212 mol

Moles of hexane :

45%=\frac{\text{moles of hexane }}{\text{Total moles}}\times 100

Moles of hexane = 5.0454 mol

Mass of 5.0454 moles of hexane,M = 5.0454 mol × 86 g/mol=433.9044 g

Density of the hexane,D = 0.655 g/cm^3

Volume of hexane = V

V=\frac{M}{D}=\frac{433.9044 g}{0.655 g/cm^3}=662.4494 cm^3\approx 0.66245 L

(1 cm^3= 0.001 L)

The required volume of hexane is 0.66245 Liters.

5 0
3 years ago
What is one thing people can do to reduce the amount of carbon in the
Nimfa-mama [501]

Answer:

B

Explanation:

Planting trees sequesters CO2

  all of the other choices produce more CO2 in the atmosphere

8 0
2 years ago
What’s the difference between 2o and o(subscript 2)?
tatuchka [14]

Answer:

2O is an atom while O2 Is a molecule

5 0
2 years ago
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