<em>Time = (the set distance) / (the object's traveling speed)</em>
Answer:
the strength of the magnetic field inside the solenoid is 6.278 x 10⁻³ T.
Explanation:
Given;
length of the wire, = 34.9 m
length of solenoid, L = 0.24 m
radius of the solenoid, r = 0.051 m
current in the solenoid, I = 11.0 A
The number of turns of the wire is calculated as follow;
The strength of the magnetic field inside the solenoid is calculated as follows;
Therefore, the strength of the magnetic field inside the solenoid is 6.278 x 10⁻³ T.
Answer:
566.3 m
Explanation:
The distance travelled by the object can be found by using the SUVAT equation:
where
u is the initial velocity
t is the time
a is the acceleration
For the object in this problem:
u = 19 m/s
a = 2.5 m/s^2
Substituting t = 15 s, we find the distance travelled:
1. Mass number = Protons + Neutrons
Mass number = 26 + 32 = 58
2. Let the element be Xy
58Xy26
3. The proton number of Strontium is 38.
Mass = 38 + 50 = 88
4. 88Sr38
5. Let the atom be Ab
72Ab32
Given Information:
diameter = d = 15 mm
Length = L = 20 mm
Axial load = P = 300 N
Eₚ = 2.70x10⁹ Pa
vₚ = 0.4
Required Information:
Change in length = ?
Change in diameter = ?
Answer:
Change in length = 0.01257 mm
Change in diameter = -0.003772 mm
Explanation:
Stress is given by
σ = P/A
Where P is axial load and A is the area of the cross-section
A = 0.25πd²
A = 0.25π(0.015)²
A = 0.000176 m²
σ = 300/0.000176
σ = 1697792.8 Pa
The longitudinal stress is given by
εlong = σ/Eₚ
εlong = 1697792.8/2.70x10⁹
εlong = 0.0006288 mm/mm
The change in length can be found by using
δ = εlong*L
δ = 0.0006288*20
δ = 0.01257 mm
The lateral stress is given by
εlat = -vₚ*εlong
εlat = -0.4*0.0006288
εlat = -0.0002515 mm/mm
The change in diameter can be found by using
Δd = εlat*d
Δd = -0.0002515*15
Δd = -0.003772 mm
Therefore, the change in length is 0.01257 mm and the change in diameter is -0.003772 mm
