peer-to-peer networks
Explanation:
Networks designed to connects similar computers that shares data and software with each other are called peer-to-peer networks.
These networks are closely around and do not rely on information passing through a central data point.
- In a peer to peer connection, the computers have direct access to one another.
- The computers over the network becomes both client and server.
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Those organic structures that do not seem to play any important biological function in the organism that possesses them are known as vestigial structures.
<h2>What is a vestigial structure?</h2>
A vestigial structure is one that has atrophied or lost its original function throughout the course of evolution.
- It generally refers to those organic structures that were useful at some point, but are now practically or totally useless.
- These structures are preserved as an inheritance of the evolutionary process, because at some point an ancestor of the current species had that structure, which was functional, but it ceased to be important and would end up atrophy.
Therefore, we can conclude that vestigial structures are structures that some organisms still conserve as an inheritance from their ancestors but that, for some reason or another, are no longer useful for the functioning of the same.
Learn more about vestigial structures here: brainly.com/question/2141655
Noise pollution, also known as environmental noise or sound pollution, is the propagation of noise with ranging impacts on the activity of human or animal life, most of them harmful to a degree.
Answer:
Explanation:
We shall represent speed in vector form
First speed
v₁ = 1.5 cos 14 i + 1.5 sin 14 j
= 1.455 i + 0.363 j
v₂ = 4.4 cos 33 i + 4.4 sin 33 j
= 3.69 i + 2.39 j
v₂ - v₁
3.69 i + 2.39 j - 1.455 i - 0.363 j
= 2.235 i + 2.027 j
acceleration
= v₂ - v₁ / time
= ( 2.235 i + 2.027 j ) / 23
= .097 i + .088 j
force = mass x acceleration
= 398 x ( .097 i + .088 j )
= 38.6 i + 35.02 j
Magnitude of force F
F² = 38.6² + 35.02²
F = 52.11 N
Tan θ = 35.02 / 38.6
θ = 42° north of east.
Answer:
121550 J
Explanation:
Parameters given:
Mass, m = 0.34kg
Specific heat capacity, c = 14300 J/kgK
Change in temperature, ΔT = 25K
Heat gained/lost by an object is given as:
Q = mcΔT
Since ΔT is positive in this case and also because we're told that heat was transferred to the hydrogen sample, the hydrogen sample gained heat. Therefore, Q:
Q = 0.34 * 14300 * 25
Q = 121550J or 121.55 kJ
