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3 years ago

Q2. Which formula represents a homogeneous mixture?

Chemistry

1 answer:

bija089 [108]3 years ago

8 0

Answer:

D) HCl(aq)

Explanation:

A homogeneous mixture can be defined as any liquid, solid or gaseous mixture which has an identical or uniform composition and properties throughout any given sample of the mixture. In Chemistry, all solutions are considered to be a homogeneous mixture.

In this scenario, the chemical formula which represents a homogeneous mixture is aqueous hydrogen chloride, HCl(aq). The aqueous hydrogen chloride is a homogeneous mixture of water and hydrogen chloride. This ultimately implies that, aqueous hydrogen chloride HCl(aq) is a solution of hydrogen chloride in water and it is commonly referred to as Hydrochloric acid.

Given by the chemical equation;

$HCl(aq) + H_{2}O(l) → H_{3}O^{+} (aq) + Cl_{−}(aq)$

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The activation energy of a certain uncatalyzed biochemical reaction is 50.0 kJ/mol. In the presence of a catalyst at 37°C, the r

rodikova [14]

Answer:

E₁ ≅ 28.96 kJ/mol

Explanation:

Given that:

The activation energy of a certain uncatalyzed biochemical reaction is 50.0 kJ/mol,

Let the activation energy for a catalyzed biochemical reaction = E₁

E₁ = ??? (unknown)

Let the activation energy for an uncatalyzed biochemical reaction = E₂

E₂ = 50.0 kJ/mol

= 50,000 J/mol

Temperature (T) = 37°C

= (37+273.15)K

= 310.15K

Rate constant (R) = 8.314 J/mol/k

Also, let the constant rate for the catalyzed biochemical reaction = K₁

let the constant rate for the uncatalyzed biochemical reaction = K₂

If the rate constant for the reaction increases by a factor of 3.50 × 10³ as compared with the uncatalyzed reaction, That implies that:

K₁ = 3.50 × 10³

K₂ = 1

Now, to calculate the activation energy for the catalyzed reaction going by the following above parameter;

we can use the formula for Arrhenius equation;

$K=Ae^{\frac{-E}{RT}}$

If $K_1=Ae^{\frac{-E_1}{RT}} -------equation 1$ &

$K_2=Ae^{\frac{-E_2}{RT}} -------equation 2$

$\frac{K_1}{K_2} = e^{\frac{-E_1-E_2}{RT}$

$E_1= E_2-RT*In(\frac{K_1}{K_2})$

$E_1= 50,000-8.314*310.15*In(\frac{3.50*10^3}{1})$

$E_1 = 28957.39292$ $J/mol$

E₁ ≅ 28.96 kJ/mol

∴ the activation energy for a catalyzed biochemical reaction (E₁) = 28.96 kJ/mol

8 0

3 years ago

Is black ok why or not

IRISSAK [1]

black is good because black was the first color ever

7 0

4 years ago

Determine the mass in grams of each of the following:

nekit [7.7K]

We know, Given mass = Molar mass * Number of moles.

A.) <span>1.25 mol CaF</span>₂

Number of moles = 1.25
Molar mass = 78

So, Mass = 78 * 1.25 = 97.5 g

B.) 3.4 mol (NH₄)₂SO₄

Number of moles = 3.4
Molar mass = 132

Mass = 3.4 * 132 = 448.8 g

Hope this helps!

3 0

3 years ago

The half- life of actinium-228 is 6.13 hours What amount of a 70 milliqram sample remains after 24.52 hours?

Usimov [2.4K]

Answer:

4.375 milligram

Explanation:

Applying,

A = A'(2ᵃ/ⁿ)............. Equation 1

Where A = original amount of actinium-228, A' = amount of actinium-228 left after decay, a = Total time, n = half life

make A' the subject of the equation

A' = A/(2ᵃ/ⁿ)........... Equation 2

From the question,

Given: A = 70 milligram, a = 24.52 hours, n = 6.13 hours

Substitute these values into equation 2

A' = 70/(2²⁴°⁵²/⁶°¹³)

A' = 70/(2⁴)

A' = 70/16

A' = 4.375 milligram

4 0

3 years ago

True or false: Halogens are very stable because they have a full outer shell of 8

STALIN [3.7K]

Answer:

True

Explanation:

Halogens are very stable because they have a full outer shell of 8

true or false?

Brainiest plz and hope this answer helped let me know if you need any more help I am glad to help!

It's true!

8 0

3 years ago