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Mila [183]
3 years ago
6

It is found when an unknown solid solute is dissolved in water that the solubility of the solid increases if temperature is decr

eased. What can be determined about the entropy and enthalpy of the dissolution of this unknown solid? not enough information to make a determination entropy is increased, exothermic entropy is decreased, exothermic entropy is increased,endothermic entropy is decreased, endothermic
Chemistry
1 answer:
mina [271]3 years ago
5 0

Answer:

exothermic entropy is increased

Explanation:

An exothermic process is one whose rate increases when the temperature is decreased. Hence if a decrease in temperature favours the dissolution of more solute at equilibrium, then the process is exothermic.

Similarly, the dissolution of a solute in a solvent increases the disorderliness (entropy) of the system because of the increase in the number of particles present. Hence once a solute in dissolved, the entropy of the system increases.

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3 years ago
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Calculate the theoretical yield for the bromination of both stilbenes
podryga [215]

Answer:

cinnamic acid - 150 mg

cis-stilbene - 100 μL

trans- stilbene - 100 mg

pyridinium tribromide - 200-385 mg

For this data:

moles of cinnamic acid = 0.150 g/148.16 g/mol = 0.001 mols

Theoretical mass of dibromoproduct formed = 0.001 mol x 307.97 g/mol = 0.312 g

cis-stilbene (100 ul = 0.1 ml)

moles of cis-stilbene = 0.1 ml x 1.01 g/mol/180.25 g/mol = 0.00056 mols

Theoretical mass of dibromoproduct formed = 0.00056 mol x 340.05 g/mol = 0.19 g

trans-stilbene

moles of tran-stilbene = 0.1 g/180.25 g/mol = 0.00055 mols

Theoretical mass of dibromoproduct formed = 0.00055 mol x 340.05 g/mol = 0.19 g

Explanation:

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2 years ago
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Answer:

AHYPOTHISES IS A GUESS

Explanation:

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