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Mila [183]
3 years ago
6

It is found when an unknown solid solute is dissolved in water that the solubility of the solid increases if temperature is decr

eased. What can be determined about the entropy and enthalpy of the dissolution of this unknown solid? not enough information to make a determination entropy is increased, exothermic entropy is decreased, exothermic entropy is increased,endothermic entropy is decreased, endothermic
Chemistry
1 answer:
mina [271]3 years ago
5 0

Answer:

exothermic entropy is increased

Explanation:

An exothermic process is one whose rate increases when the temperature is decreased. Hence if a decrease in temperature favours the dissolution of more solute at equilibrium, then the process is exothermic.

Similarly, the dissolution of a solute in a solvent increases the disorderliness (entropy) of the system because of the increase in the number of particles present. Hence once a solute in dissolved, the entropy of the system increases.

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garri49 [273]

Explanation:

Given

The enthalpy of formation of RbF (s) is –557.7kJ/mol

The standard enthalpy of formation of RbF (aq, 1 m) is –583.8 kJ/mol

The enthalpy of solution of RbF = Enthalpy of RbF (aq) - Enthalpy of formation of RbF (s)

= -583.8 - (-557.7)  kJ/mol

= -26.1 kJ/mol

The enthalpy is negative which means that the temperature will rise when RbF is dissolved.

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We have been told in the question that the solid does not really dissolve in water and it's solution does not improve the electrical conductivity of water. Hence, it must be a molecular solid.

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