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Molodets [167]
3 years ago
10

HEEELPPP PLEASSEEEE HURRY

Physics
1 answer:
tino4ka555 [31]3 years ago
5 0

Answer:

Release correct vygygyvybuhibin

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The kinetic energy of a 10-kilogram object is 2000 joules. What is the speed of the object, in m/s?
Svetllana [295]

Answer:

<u><em>20 m/s.</em></u>

Explanation:

Mass of body m: 10kg

The kinetic energy of the body is given as; K.E= \frac{1}{2} * m * v^{2}

Value of Kinetic energy K.E = 2000 Joules

V is the body's velocity, and M is the body's mass.

Calculating the value of velocity; V=\frac{\sqrt{2K*E} }{m}  V= \frac{\sqrt{2*2000} }{10}  = V=20m/s

Velocity maintained by the body having a kinetic energy of 2000J is

20 m/s.

6 0
2 years ago
What wave property increases as the number of vibrations producing the wave increases?
suter [353]
The frequency of the wave increases as it is the number of oscillations per second.
8 0
3 years ago
Read 2 more answers
A tank contains 0.568 mol of molecular nitrogen (N2). Determine the mass (in grams) of nitrogen that must be removed from the ta
Marizza181 [45]

Answer:

\Delta M = 7.812 gm

Explanation:

we know that for ideal gag we have

pV =nRT

Since volume, gas constant R and T are constant, so we have

\frac{p}{n]  = constant

\frac{44.7}{0.568} =\frac{22.8}{n}

n = 0.289 mole

hence mass removed\Delta M =( 0.568 - 0.289)*( molecular\ weight\ of \ nitrogen)

\Delta M = (0.568 - 0.289) *28 gm

\Delta M = 7.812 gm

8 0
4 years ago
Mechanical energy is similar to thermal energy because they both?
katrin [286]

Answer:

Mechanical energy is the ordered movement of the molecules as a single unit. Thermal energy is the random movement of the molecules. Mechanical energy can be 100% converted to thermal energy, but thermal energy cannot be fully converted to mechanical energy.

7 0
2 years ago
Which of the following (with specific heat capacity provided) would show the smallest temperature change upon gaining 200.0 J of
sergij07 [2.7K]

Answer:

A) 50.0 g Al

Explanation:

We can calculate the temperature change of each substance by using the equation:

\Delta T=\frac{Q}{mC_s}

where

Q = 200.0 J is the heat provided to the substance

m is the mass of the substance

C_s is the specific heat of the substance

Let's apply the formula for each substance:

A) m = 50.0 g, Cs = 0.903 J/g°C

\Delta T=\frac{200}{(50)(0.903)}=4.4^{\circ}C

B) m = 50.0 g, Cs = 0.385 J/g°C

\Delta T=\frac{200}{(50)(0.385)}=10.4^{\circ}C

C) m = 25.0 g, Cs = 0.79 J/g°C

\Delta T=\frac{200}{(25)(0.79)}=10.1^{\circ}C

D) m = 25.0 g, Cs = 0.128 J/g°C

\Delta T=\frac{200}{(25)(0.128)}=62.5^{\circ}C

E) m = 25.0 g, Cs = 0.235 J/g°C

\Delta T=\frac{200}{(25)(0.235)}=34.0^{\circ}C

As we can see, substance A) (Aluminium) is the one that undergoes the smallest temperature change.

7 0
3 years ago
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