Kx = F
k * 0.1 = 50
k = 50/0.1 = 500 N/m
Answer:
Now e is due to the ring at a
So
We say
1/4πEo(ea/ a²+a²)^3/2
= 1/4πEo ea/2√2a³
So here E is faced towards the ring
Next is E due to a point at the centre
So
E² = 1/4πEo ( e/a²)
Finally we get the total
Et= E²-E
= e/4πEo(2√2-1/2√2)
So the direction here is away from the ring
Explanation:
The temperature of the solar nebula was decreasing as it moved away from its center. Therefore, only heavy elements could condense in the inner solar system and terrestrial planets could not form with light elements, such as gases. In the outer solar system, the Jovian planets formed mostly with gases, since temperatures were too low to allow rocky compositions.
Remark
Always write down your givens and what you want to find. The formula you use for such questions will suggest itself if you do this.
Givens
a = 3.0 m/s^2
vi = 0 I presume that's that the question assumes.
vf = 33 m/s
You want d
Formula
vf^2 = vi^2 + 2*a*d
Solution
33^2 = 0^2 + 2 * 3 * d
1089 = 6*d
d = 1089/6
d = 181.5 meters
