Answer:
Condition
Explanation:
Basically black hole is an object from which light rays can not escape it means to go out from gravitational field , that body should thrown with speed greater then light.
Let's do some calculation
Gravitational potential at surface =
If we give kinetic energy equal to magnitude of Potential energy as on surface it will escape.
=
⇒
It will be more better for black hole if above ratio (analogous to density ) is more then above calculated
Answer:
Time = 1.75[s]; Distance traveled = 21.5 [m]; Max height = 15 [m]
Explanation:
First, we have to break down the velocity vector into the X & y components.
To find the time t that lasts the ball of cannon in the air we must use the following equation of kinematics, in this equation the value of y is equal to zero because it will be proposed that the ball lands at the same level that was fired.
In order to find the distance traveled horizontally from the cannonball, we must use the speed kinematics equation in the X coordinate.
In order to find the last value, we must bear in mind that when the cannonball reaches the maximum height, the velocity in the component y is equal to zero, and we can find the value of and with the following kinematic equation
Answer:
I looked it up but got perihelion so I don't know if that will help at all but try um.... I don't know try L
Explanation:
Answer:
117.6°
Explanation:
The vertical component of a force directed at some angle α from the vertical is ...
F·cos(α)
We want the vertical components of the wolf's force (Fw) and Red's force (Fr) to total zero. So for some angle from vertical α, Red's force will satisfy ...
Fw·cos(25°) + Fr·cos(α) = 0
cos(α) = -Fw/Fr·cos(25°) ≈ -(6.4 N)/(12.5 N)·0.906308 ≈ -0.464030
α ≈ arccos(-0.464030) ≈ 117.6°
Red was pulling at an angle of about 117.6° from the vertical.
_____
<em>Additional comment</em>
That's about 27.6° below the horizontal.
"Oscilloscope" can be used to show the shape of a sound wave
Hope this helps!