Answer:
6,600N
Explanation:
According to second law of motion, Force = mass × acceleration
If acceleration = change in velocity/time = 15/0.10
Acceleration = 150m/s²
Given mass = 44kg
Force = 44× 150
Force = 6,600N
Magnitude of the average force exerted on the passenger during this time is 6,600N
Answer:
887.1Hz
Explanation:
Given parameters:
Speed of sound wave = 330m/s
Wavelength = 0.372m
Unknown:
Frequency = ?
Solution:
To solve this problem, we use the expression below:
Speed = Frequency x wavelength
330 = Frequency x 0.372
Frequency = 887.1Hz
Answer:
(a) When the resultant force is pointing along east line, the magnitude and direction of the second force is 280 N East
(b) When the resultant force is pointing along west line, the magnitude and direction of the second force is 560 N West
Explanation:
Given;
a force vector points due east,
= 140 N
let the second force = 
let the resultant of the two vectors = F
(a) When the resultant force is pointing along east line
the second force must be pointing due east


(b) When the resultant force is pointing along west line
the second force must be pointing due west and it must have a greater magnitude compared to the first force in order to have a resultant in west line.


The best answer to go with is b
Answer: An object undergoing uniform circular motion is moving
Explanation: