Answer:
m = 9.6 g
Explanation:
Thermal energy given to helium gas at constant volume is given as

so here we have



so we have

now we know that
for oxygen gas we have

for same amount of heat we have




 
        
             
        
        
        
Answer:
Explanation:
Appears to be the vertexes of a triangle.
AB = √(-6 - (-2))² + (3 - 4)²) = √17
AC = √(-6 - (-8))² + (3 - 3)²) = 2
BC = √(-2 - (-8))² + (4 - 3)²) = √37
 
        
             
        
        
        
It would be easier to answer your question if you attached options. Anyway I remember that the right answer to that question is:<span> marissa, because she has cheered for the team all season long</span>
        
             
        
        
        
Answer:
Shiny metals such as copper, silver, and gold are often used for decorative arts, jewelry, and coins.
Strong metals such as iron and metal alloys such as stainless steel are used to build structures, ships, and vehicles including cars, trains, and trucks.
Some metals have specific qualities that dictate their use. For example, copper is a good choice for wiring because it is particularly good at conducting electricity. Tungsten is used for the filaments of light bulbs because it glows white-hot without melting.
Nonmetals are plentiful and useful. These are among the most commonly used:
Oxygen, a gas, is absolutely essential to human life. Not only do we breathe it and use it for medical purposes, but we also use it as an important element in combustion.
Sulfur is valued for its medical properties and as an important ingredient in many chemical solutions. Sulfuric acid is an important tool for industry, used in batteries and manufacturing.
Chlorine is a powerful disinfectant. It is used to purify water for drinking and fill swimming pools.
Explanation:
 
        
             
        
        
        
Answer:
It will take 15.55s for the police car to pass the SUV
Explanation:
We first have to establish that both the police car and the SUV will travel the same distance in the same amount of time. The police car is moving at constant velocity and the SUV is experiencing a deceleration. Thus we will use two distance fromulas (for constant and accelerated motions) with the same variable for t and x:
1. 
2. 
Since both cars will travel the same distance x, we can equal both formulas and solve for t:

We simplify the fraction present and rearrange for our formula so that it equals 0:

In the very last step we factored a common factor t. There is two possible solutions to the equation at  and:
 and:

What this means is that during the displacement of the police car and SUV, there will be two moments in time where they will be next to each other; at  (when the SUV passed the police car) and
 (when the SUV passed the police car) and  (when the police car catches up to the SUV)
(when the police car catches up to the SUV)