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solmaris [256]
3 years ago
13

Omar heated a small piece of calcium carbonate. It gave off carbon dioxide gas, solid calcium oxide was left behind.write equati

on.
Chemistry
1 answer:
Airida [17]3 years ago
5 0

Answer:

CaCO_{3s}  →  CO_{2g}   +   CaO_{s}  

Explanation:

Given reactants:

 Omar heated small piece of calcium carbonate

Product;

  it gave off carbon dioxide gas and solid calcium oxide;

Problem,

Equation of the reaction;

Solution:

 

 Calcium carbonate →  Carbon dioxide + Calcium oxide

           CaCO_{3s}  →  CO_{2g}   +   CaO_{s}  

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Mamont248 [21]

Answer:

I think the answer is B or Compounds

3 0
3 years ago
How many grams of silver nitrate are needed to react with 156.2g of sodium sulfide to produce 595.8g of silver sulfide and 340.0
qaws [65]
Before proceeding, we should write the reaction equation to better understand what is happening:
2AgNO₃ + Na₂S → Ag₂S + 2NaNO₃

Now, we may apply the law of conservation of mass, due to which the total mass before a chemical reaction is equivalent to the total mass after a chemical reaction. Therefore:
Mass of silver nitrate + mass of sodium sulfide = mass of silver sulfide + mass of sodium nitrate

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3 0
3 years ago
A chemical equation is shown: C2H4 + O2 → CO2 + H2O According to the law of conservation of mass, how many atoms of oxygen exist
astraxan [27]

Answer:

6 oxygens on the product side

Explanation:

1) balance the equation:

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6 0
3 years ago
How many formula units are there in 450 g of Na2S04?
Mashutka [201]

Formula units in 450 g of Na_{2} So_{4} is 1.93 × 10²⁴ formula units.

<u>Explanation:</u>

First we have to find the number of moles in the given mass by dividing the mass by its molar mass as,

$\frac{450 g}{142.04 g/mol} =  3.2 moles

Now, we have to multiply the number of moles of Na₂SO₄ by the Avogadro's number, 6.022 × 10²³ formula units/mol, so we will get the number of formula units present in the given mass of the compound.

3.2 mol × 6.022 × 10²³ = 1.93 × 10²⁴ formula units.

So, 1.93 × 10²⁴ formula units is present in 450g of Na₂SO₄.

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