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Temka [501]
3 years ago
5

1. Describe the general procedure on how to wash glassware used for organic lab experiments. Also, include what the common solve

nt used to wash organic glassware
Chemistry
1 answer:
Gemiola [76]3 years ago
5 0

Explanation:

As a number of glassware are used in lab experiments so it is necessary that they should be cleaned properly after and before the experiment.

This can be done as follows.

1). At first acetone is used to rinse the glassware. If water soluble contents present in the glassware then use deionized water after rinsing it with acetone and if ethanol soluble components are present there then rinse with ethanol followed by rinses with deionized water.

2). When glassware are dirty in such a manner that they cannot be washed immediately then soak them in water for a certain period of time. This can help in removing the dirt or chemicals easily from the glassware.

3). The laboratory glassware can be easily washed with detergents or products like lab wash, alconox etc. Once these glassware are thoroughly cleaned then rinse them 3 times with deionized water.

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Calculate the volume in Liters of 15 moles of Neon gas (at STP)
Archy [21]
Step by step solution:

Its given;
Moles of neon at STP is 15 mol
We are required to calculate the volume;
According to molar gas volume, 1 mole of a gas occupies a volume of 22.4 liters at STP.
That is, 1 mole of a gas = 2.4 L
Therefore;
1 mole of Neon gas = 22.4 L

Volume = Moles of the gas × molar gas volume
= 15 mol × 22.4 L/mol
= 336 L
5 0
3 years ago
Examine the fossil. List the parts of the animal that you recognize. What kind of animal do you think this was?
netineya [11]

Answer:

I think it was a huge fish. umm not sure

Explanation:

3 0
3 years ago
How many liters of hydrogen gas are required to react with 3.5" liters of oxygen gas in the following reaction? 2H2(g)+O2(g) --&
Hatshy [7]

Answer:

7 L of H₂.

Explanation:

The balanced equation for the reaction is given below:

2H₂ + O₂ —> 2H₂O

From the balanced equation above,

1 L of O₂ required 2 L of H₂.

Finally, we shall determine the volume of H₂ required to react with 3.5 L of O₂. This can be obtained as follow:

From the balanced equation above,

1 L of O₂ required 2 L of H₂.

Therefore, 3.5 L of O₂ will require

= 3.5 × 2 = 7 L of H₂.

Thus, 7 L of H₂ is required to for the reaction.

5 0
3 years ago
At what temperature will 0.654 moles of helium gas occupy 12.30 liters at 1.95 atmospheres?
DedPeter [7]

Answer:

447,25k

Explanation:

According to the ideal gas law

PV=nRT

Where:

P: is the pressure of the gas in atmospheres.

V: is the volume of the gas in liters.

n: number of moles of the gas

R: ideal gas constant

T: absolute temperature of the gas in kelvin

now using:

T=\frac{PV}{nR}\\ \\T=\frac{12,3L.1,95atm}{0,654mol.0,082(L.atm/K.mol)}\\ \\T=447,25K

3 0
3 years ago
Solid chromium (III) reacts with oxygen gas to form solid Cr2O3. What is this type of reaction?
mafiozo [28]

Answer:

.081 g of O2

Explanation:

4Cr + 3O2 -----> 2Cr2O3

.175 g Cr x [1 mole / 52.0 g] x [2 moles Cr2O3 / 4 moles Cr] x [152 g / 1 mole] = .256 g of Cr2O3

.175 g Cr x [1 mole / 52.0 g] x [3 moles O2 / 4 moles Cr] x [32 g / 1 mole] = .081 g of O2

5 0
3 years ago
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