Step by step solution:
Its given;
Moles of neon at STP is 15 mol
We are required to calculate the volume;
According to molar gas volume, 1 mole of a gas occupies a volume of 22.4 liters at STP.
That is, 1 mole of a gas = 2.4 L
Therefore;
1 mole of Neon gas = 22.4 L
Volume = Moles of the gas × molar gas volume
= 15 mol × 22.4 L/mol
= 336 L
Answer:
I think it was a huge fish. umm not sure
Explanation:
Answer:
7 L of H₂.
Explanation:
The balanced equation for the reaction is given below:
2H₂ + O₂ —> 2H₂O
From the balanced equation above,
1 L of O₂ required 2 L of H₂.
Finally, we shall determine the volume of H₂ required to react with 3.5 L of O₂. This can be obtained as follow:
From the balanced equation above,
1 L of O₂ required 2 L of H₂.
Therefore, 3.5 L of O₂ will require
= 3.5 × 2 = 7 L of H₂.
Thus, 7 L of H₂ is required to for the reaction.
Answer:
447,25k
Explanation:
According to the ideal gas law

Where:
P: is the pressure of the gas in atmospheres.
V: is the volume of the gas in liters.
n: number of moles of the gas
R: ideal gas constant
T: absolute temperature of the gas in kelvin
now using:

Answer:
.081 g of O2
Explanation:
4Cr + 3O2 -----> 2Cr2O3
.175 g Cr x [1 mole / 52.0 g] x [2 moles Cr2O3 / 4 moles Cr] x [152 g / 1 mole] = .256 g of Cr2O3
.175 g Cr x [1 mole / 52.0 g] x [3 moles O2 / 4 moles Cr] x [32 g / 1 mole] = .081 g of O2