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bulgar [2K]
3 years ago
14

What is life like in a cave camp? Do you think you would like to experience this? Why or why not?

Physics
1 answer:
GalinKa [24]3 years ago
3 0

Answer:

There's no risk of animals or bad weather interfering with your campsite, either. You don't even really need a tent. A sleeping pad, sleeping bag and a mindful eye to pick up everything you brought in is all you really need to enjoy overnight caving. Do your research

Explanation:

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True or false? Once the sun explodes, the whole solar system will go with it.
liberstina [14]
True. That is how powerful the sun is. But it will explode in only about 5 billion years.
6 0
3 years ago
How many bases are there in baseball before reaching home plate?
gregori [183]
There are 3 bases before you reach home plate.
5 0
3 years ago
A rectangular barge, 5.2 m long and 2.4 m wide, floats in fresh water. Suppose that a 410-kg crate of auto parts is loaded onto
sesenic [268]
<h2>Answer:</h2><h2>The depth of barge float=3 cm</h2><h2>Explanation:</h2>

Length of rectangular barge=5.2 m

Width of rectangular barge=2.4m

Mass of crate=410 kg

Let h be the height of barge float

Volume of barge float=l\times b\times h=5.2\times 2.4\times h=12.48h

Density of water=10^3kg/m^3

Weight of water displaced by barge=Buoyant force=-Weight of horse

Volume\;of\;water\times density\;of\;water\times g=410\times g

12.48h\times 1000=410

h=\frac{410}{12.48\times 1000}=0.03 m

1 m=100 cm

0.03 m=0.03\times 100=3cm

Hence, the depth of barge float=3 cm

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4 0
3 years ago
Read 2 more answers
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kolbaska11 [484]

Answer: 2.2x10^4

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4 0
2 years ago
The efficiency of a device such as a lamp can be calculated using this equation:
loris [4]

efficiency = (useful energy transferred ÷ energy supplied) × 100

It's easy to use this formula, but we have to know both the useful energy and the energy supplied.  The drawing doesn't tell us the useful energy, so we have to find a clever way to figure it out.  I see two ways to do it:

<u>Way #1:</u>

We all know about the law of conservation of energy.  So we know that the total energy coming out must be  250J, because that's how much energy is going in.  The wasted energy is 75J, so the rest of the 250J must be the useful energy . . . (250J - 75J) = 175J useful energy.

(useful energy) / (energy supplied) =  (175J) / (250J) = <em>70% efficiency</em>

================================

<u>Way #2: </u>

How much of the energy is wasted ? . . . 75J wasted

What percentage of the Input is that 75J ? . . . 75/250 = 30% wasted

30% of the input energy is wasted.  That leaves the other <em>70%</em> to be useful energy.

6 0
2 years ago
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