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3 years ago

a light wave travels at 3.0 x 10^8 m/s. if the wavelength of a red wave is 700 x 10^-9m, what is the frequency?

1 answer:

3 0

Frequency = (speed) divided by (wavelength)

   = (3 x 10⁸ m/s) / (700 x 10⁻⁹ m)

   = (3 / 700) x 10¹⁷ ( per sec )

   = 4.286 x 10¹⁴ per sec = 4.286 x 10¹⁴ Hz.

   = 42,860 GHz .

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Three 7 0hm resistors are connected in series across a 10 V battery. What is the equivalent resistance of the circuit?

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Given

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$R=7+7+7=21\Omega$

Conclusion

The equivalent resistance is 21 ohm

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3 years ago

A piano emits frequencies the range from a low of about 28 Hz to a high of about 4200 Hz. Find the range of wavelengths in air a

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V=wave velocity , f= frequency, λ=wavelength 
Use it to find corresponding wavelengths for f=28 Hz 
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3 years ago

Two electrodes, separated by a distance d, in a vacuum are maintained at a constant potential difference. An electron, accelerat

Alja [10]

Answer:

Explanation:

Given that, the distance between the electrode is d.

The electron kinetic energy is Ek when the electrode are at distance "d" apart.

So, we want to find the K.E when that are at d/3 distance apart.

K.E = ½mv²

Note: the mass doesn't change, it is only the velocity that change.

Also,

K.E = Work done by the electron

K.E = F × d

K.E = W = ma × d

Let assume that if is constant acceleration

Then, m and a is constant,

Then,

K.E is directly proportional to d

So, as d increase K.E increase and as d decreases K.E decreases.

So,

K.E_1 / d_1 = K.E_2 / d_2

K.E_1 = E_k

d_1 = d

d_2 = d/3

K.E_2 = K.E_1 / d_1 × d_2

K.E_2 = E_k × ⅓d / d

Then,

K.E_2 = ⅓E_k

So, the new kinetic energy is one third of the E_k

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3 years ago