How would we do that here
Answer:
y = x/2 - 7
Step-by-step explanation:
First, we need to find the slope of the given equation: x - 2y = 8
Subtract x from both sides
x - 2y = 8
- x - x
-2y = 8 - x
Divide both sides by -2
-2y/-2 = (8 - x)/-2
y = -4 + x/2
The slope of this equation is 1/2
So the equation of our parallel equation is y = x/2 + b
We have to find b, so plug in the given coordinates
-6 = 2/2 + b
-6 = 1 + b
Subtract 1 from both sides
-6 = 1 + b
- 1 - 1
b = -7
Plug it back into the original equation
y = x/2 - 7
Answer: w=12, y=6√3
Step-by-step explanation:
Looking at the figure, we can split the triangle into 2 separate triangles. One on the left and one on the left. The triangle on the right is a 30-60-90 triangle. For this triangle, the hypotenuse is 2x in length. This is directly opposite of the right angle. The leg opposite to 30° is x in length. The leg opposite 60° is x√3 in length. Once you know the length of one side, you can plug in x to find the length of the other legs.
In this case, w and y are located on the same 30-60-90 triangle. Normally we would focus on that triangle to find our values, but in this instance, we don't have any values. We have to use the left triangle to find the leg that both triangles share.
The left triangle is a 45-45-90 triangle. For this triangle, the legs opposite of 45° is x in length. The hypotenuse is x√2. Since we know the hypotenuse, we can use it to find x.
x√2=8
x=8/√2
x=5.7 or 6 [Let's use 6 so that it is easier to work with a whole number]
Now that we know x, we can find w and y. Going back to the right triangle, we know the hypotenuse is 2x. We plug in 6 to find the length.
w=2x
w=2(6)
w=12
We know the leg opposite of 60° is x√3. We can plug in x.
y=6√3
Answer: The average of the first two test scores is 97.
Step-by-step explanation: Given that Kristie has taken five tests in science class. The average of all five of Kristie's test scores is 94 and the average of her last three test scores is 92.
We are to find the average score of her first two tests.
Let a1, a2, a3, a4 and a5 be teh scores of Kristle in first , second, third, fourth and fifth tests respectively.
Then, according to the given information, we have
and
Subtracting equation (ii) from equation (i), we get
Thus, the average of the first two test scores is 97.
