Find the remainder when x3 - 2x2 + x + 1 is divided by (x - 2).?

Mathematics

1 answer:

Basile [38]3 years ago

4 0

3/(x-2)

The answer is x^2+1+3/(x-2)

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(10 pts) (a) (2 pts) What is the difference between an ordinary differential equation and an initial value problem? (b) (2 pts)

laiz [17]

Answer:

Step-by-step explanation:

(A) The difference between an ordinary differential equation and an initial value problem is that an initial value problem is a differential equation which has condition(s) for optimization, such as a given value of the function at some point in the domain.

(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.

(C) Example of a second order linear ODE:

M(t)Y"(t) + N(t)Y'(t) + O(t)Y(t) = K(t)

The equation will be homogeneous if K(t)=0 and heterogeneous if $K(t)\neq 0$

Example of a second order nonlinear ODE:

$Y=-3K(Y){2}$

(D) Example of a nonlinear fourth order ODE:

$K^4(x) - \beta f [x, k(x)] = 0$

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3 years ago

Is 4 3/5 - 3 3/4 greater than or less than 1

Jlenok [28]

Answer:

less because it equals 0.85

Step-by-step explanation:

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2 years ago

Fine the equation of the line that is perpendicular to the given line and passes through the given point. Enter the right side o

Kipish [7]

Answer:

$y=-\frac{4}{7} x+\frac{55}{7}$

Step-by-step explanation:

Change the given equation to slope-intercept to get $y=\frac{7}{4}x-\frac{1}{4}$ . When you multiply the slopes of perpendicular lines, you get -1. -1 divided by $\frac{7}{4}$ is $-\frac{4}{7}$ . The slope of the new line is then $-\frac{4}{7}$ . The perpendicular line passes through (5, 5) so you can have the equation $5=-\frac{4}{7} (5)+b$ . Simplifying gets $b = \frac{55}{7}$ . So now the final equation for the perpendicular line is $y=-\frac{4}{7} x+\frac{55}{7}$