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otez555 [7]
3 years ago
14

6.20 A divided multilane highway in a recreational area has four lanes (two lanes in each direction) and is on rolling terrain.

The highway has 10-ft lanes with a 6-ft right-side shoulder and a 3-ft left-side shoulder. The posted speed is 50 mi/h. Previously, there were 4 access points per mile, but recent development has increased the number of access points to 12 per mile. Before development, the peak-hour factor was 0.95 and the directional hourly volume was 2200 vehicles with 13% heavy vehicles. After development, the peak-hour directional flow is 2600 vehicles with the same vehicle percentages and peak-hour factor. What is the level of service before and after the development
Engineering
1 answer:
Taya2010 [7]3 years ago
5 0

Answer:

A) Level D ( before development )

B) Level E ( After development )

Explanation:

A) Calculate the level of service before the development

First we calculate the base free flow speed ( BFFS )

= posted speed limit  + 5 mi/hr.

= 50 + 5 = 55mi/hr.

Next determine free flow speed ( FFS )

= BFFS - f_{lw} - f_{lc}  - f_{m}  - f_{A}

= 55 - 6.6 - 0.65 - 0 - 2.25 = 45 mi/hr.

The remaining part of the solution is attached below

The level of service = D

given that:

Vp = 1537.096 pc/hr/In

Density = 34.157 pc/mi/In

FFS = 45 mi/hr

B ) Calculate the level of service after the development

attached below is the detailed solution

The level of service = E

given that

Vp = 1816.568 pc/hr/In

Density = 40.368 pc/mi/In

FFS = 45 mi/hr

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Write the definitions for engineering stress, true stress, engineering strain, and true strain for loading along a single axis.
shusha [124]

Answer and Explanation:

Engineering Stress of a material is defined as the applied load or force divided by the original cross sectional Area of the material.

σ(engineering) = F/(Ao)

True Stress is defined as the applied load or force divided by the actual cross-sectional area (the changing area with respect to time) of the material at that point in time. It's an instantaneous stress.

σ(true) = F/A

Engineering strain is a measure of how much a material deforms under a particular load. It is the amount of deformation in the direction of the applied force divided by the initial length of the material.

ε(engineering) = Δl/lo

True Strain measures instantaneous deformation. It is obtained mathematically by integrating strain over small time periods and summing them up. Hence,

ε(true) = In (lf/lo)

The calculations,

First step, 10m to 10.1m, Δl = 0.1m, lf = 10.1m, lo = 10m

ε(engineering) = 0.1/10 = 0.01

ε(true) = In (10.1/10) = 0.00995

Second step, 10.1m to 10.2m, Δl = 0.1m, lf = 10.2m, lo = 10.1m

ε(engineering) = 0.1/10.1 = 0.0099

ε(true) = In (10.2/10.1) = 0.00985

Overall, 10m to 10.2m, Δl = 0.2m, lf = 10.2m, lo = 10m

ε(engineering) = 0.2/10 = 0.02

ε(true) = In (10.2/10) = 0.0198

QED!

5 0
3 years ago
Technician A says that a 12 Volt light bulb that draws 12 amps has a power output of 1 watt. Technician B says that a motor that
Artemon [7]

Answer:

Technician B

Explanation:

Resistance, R=\frac {V}{I} where V is the voltage and I is the current in amps

Therefore, R=\frac {12}{12}=1 ohm

Power=VI=12*12=144 W

Therefore, the power is 144 W and resistance is 1 Ohm. This implies that technician A is wrong while technician B is correct

6 0
4 years ago
40 points! helppppp Directions:
julsineya [31]

Answer:

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Loans and reward plans proposed immediately to business people are one way to use tax revenue to arouse business ventures.

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6 0
3 years ago
A slight breeze is blowing over the hot tub above and yields a heat transfer coefficient h of 20 W/m2 -K. The air temperature is
patriot [66]

Answer:4050 W

Explanation:

Given

Heat transfer Coefficient(h)=20 W/m^2-K

Air temperature =75 F

surface area(A)=7.5 m^2

Temperature of hot tube is 102 F

We know heat transfer due to convection is given by

Q=hA\left ( \Delta T\right )

Q=20\times 7.5\left ( 102-75\right )=4050 W

7 0
3 years ago
An experiment compares the initial speed of bullets fired from two handguns: a 9 mm and a 0.44 caliber. The guns are fired into
olasank [31]

Answer:

1.176

Explanation:

When the bullets impact the mass they become embedded on it, it is a plastic collision, therefore momentum is conserved.

v2 * (M + mb) = v1 * mb

Where

v1: muzzle velocity of the bullet

M: mass of the bob

mb: mass of the bullet

v2: mass of the bob with the bullet after being hit

v2 = v1 * mb / (M + mb)

Upon being impacted the bob will acquire speed v2, this implies a kinetic energy. The bob will then move and raise a height h. Upon acheiving the maximum height it will have a speed of zero. At that point all kinetic energy will be converted into potential energy.

Ek = 1/2 (M + mb) * v2^2

Ep = (M + mb) * g * h

Ek = Ep

1/2 (M + mb) * v2^2 = (M + mb) * g * h

1/2 * (v1 * mb / (M + mb))^2 = g * h

1/2 * v1^2 * mb^2 / (M + mb)^2 = g * h

v1^2 = g *h * (M+ mb)^2 / (1/2 * mb^2)

v2 = \sqrt{\frac{g *h * (M+ mb)^2}{\frac{1}{2} * mb^2}}

The height h that it reaches is related to the length L of the pendulum arm and the angle it forms with the vertical.

h = L * (1 - cos(a))

v2 = \sqrt{\frac{g * L * (1 - cos(a)) * (M+ mb)^2}{\frac{1}{2} * mb^2}}

For the 9 mm:

v2 = \sqrt{\frac{9.81 * L * (1 - cos(4.3)) * (10+ 0.006)^2}{\frac{1}{2} * 0.006^2}} = \sqrt{L} * 391

For the 0.44 caliber:

v2 = \sqrt{\frac{9.81 * L * (1 - cos(10.1)) * (10+ 0.012)^2}{\frac{1}{2} * 0.012^2}} = \sqrt{L} * 460

The ratio is 460 / 391 = 1.176

6 0
3 years ago
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