Answer:
freeeeeeeeeeeeeeeeeeeeeeeee
Explanation:
VVVVVVVVVVVVVVVVVVVVV
Answer:
True :)
Explanation:
If this is a true or false question.
Kamwiisyveu ajoae iosiwnjije j’dis ke si
The magnitude of applied stress in the direction of 101 is 12.25 MPA and in the direction of 011, it is not defined.
Explanation:
Given:
tensile stress is applied parallel to the [100] direction
Shear stress is 0.5 MPA.
To calculate:
The magnitude of applied stress in the direction of [101] and [011].
Formula:
zcr=σ cosФ cosλ
Solution:
For in the direction of 101
cosλ = (1)(1)+(0)(0)+(0)(1)/√(1)(2)
cos λ = 1/√2
The magnitude of stress in the direction of 101 is 12.25 MPA
In the direction of 011
We have an angle between 100 and 011
cosλ = (1)(0)+(0)(-1)+(0)(1)/√(1)(2)
cosλ = 0
Therefore the magnitude of stress to cause a slip in the direction of 011 is not defined.
Answer:
Copy MATLAB code to plot the magnitude of magnetic field strength with respect to z on the axis of solenoid:
z=-20:0.01:20;
H=120.*(((20-(2.*z))./sqrt((20-(2.*z)).^2+100))+((20+(2.*z))./sqrt((20+(2.*z)).^2+100)));
plot(z,H)
title('plot of |H| vs z along the axis of solenoid')
ylabel('Magnitude of magnetic field 'H")
xlabel('position on axis of solenoid 'z")
Explanation:
full explanation is attached as picture and the resultant plot also.
