About how long does it take earth to make a make 1 revolution around the sun a a day be a week see a month d a year

1 answer:

6 0

Wait what? I can’t understand. But here is what I understood. About how long does it take the Earth to make 1 revolution around the sun? Answer: 365 days

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Describe the motion of the object in Graph B of figure 11-2.

kupik [55]

Answer : The motion of the object is, non-uniform

Explanation :

Uniform motion : It is defined as the movement of an object along a straight line with constant speed. It travels equal distances in equal time interval.

The average speed of an object is similar to the actual speed of an object. The distance-time graph shows a straight line.

Non-uniform motion : It is defined as the movement of an object along a straight line with variable speed. It travels unequal distances in equal time interval.

The average speed of an object is different to the actual speed of an object. The distance-time graph shows a curved line.

The given graph B is a non-uniform motion graph.

Hence, the motion of the object is, non-uniform

4 0

4 years ago

Read 2 more answers

The process of physically separating a single-phase mixture into components if the components have different boiling points is c

kobusy [5.1K]

This process of physically separating a single phase mixture into several components would be termed simple distillation, I believe.

As it is mentioned that one is separating them based on their different boiling points.

6 0

4 years ago

The only force acting on a 1.9 kg canister that is moving in an xy plane has a magnitude of 3.9 N. The canister initially has a

Hunter-Best [27]

Answer:

The work done on the canister is 15.34 J.

Explanation:

Given;

mass of canister, m = 1.9 kg

magnitude of force acting on x-y plane, F = 3.9 N

initial velocity of canister in positive x direction, $v_i$ = 3.9 m/s

final velocity of the canister in positive y direction, $v_j = 5.6 \ m/s$

The change in the kinetic energy of the canister is equal to net work done on the canister by 3.9 N.

ΔK.E = $W_{net}$

ΔK.E $= K.E_f -K.E_i$

The initial kinetic energy of the canister;

$K.E_i = \frac{1}{2} mv_i^2\\\\K.E_i = \frac{1}{2} m(\sqrt{v_i^2 +v_j^2 + v_z^2}\ )^2\\\\K.E_i = \frac{1}{2} *1.9(\sqrt{3.9^2 +0^2 + 0^2}\ )^2 = 14.45 \ J$

The final kinetic energy of the canister;

$K.E_f =\frac{1}{2} mv_j^2 \\\\K.E_f = \frac{1}{2} m(\sqrt{v_i^2 +v_j^2 + v_z^2}\ )^2\\\\K.E_f = \frac{1}{2} *1.9(\sqrt{0^2 +5.6^2 + 0^2}\ )^2 = 29.79 \ J$